我创建了一个响应式sap.m.table。但我无法从数据对象加载值。我想申请“subvariants”数组对象。帮助
summaryDetailData={"subvariants":[{"currentValue":"","Article":"1234567","question":"Carpet Installation type"},{"currentValue":"","question":"CarpetQuantity"},{"currentValue":"","Article":"1234568","question":"Underpad type"},{"currentValue":"","question":"UnderpadQuantity"},{"currentValue":false,"Article":"1234568","question":"Rapid Install"}]}
var oTable = new sap.m.Table("idRandomDataTable", {
headerToolbar: new sap.m.Toolbar({
content: [
new sap.m.Label({text: "Summary Data"}),
new sap.m.ToolbarSpacer({}),
new sap.m.Button("idPersonalizationButton", {
icon: "sap-icon://person-placeholder"
})]}),
columns: summaryDetailData.cols.map(function (colname) {
return new sap.m.Column({ header: new sap.m.Label({ text: colname })})
})
});
oTable.setModel(new sap.ui.model.json.JSONModel(summaryDetailData));
oTable.bindAggregation("subvariants", "/subvariants", new sap.m.ColumnListItem({
cells: oData.cols.map(function (colname) {
return new sap.m.Label({ text: "{" + colname.toLowerCase() + "}" })
})
}));
答案 0 :(得分:8)
将模型绑定到表的方式并不完全正确。您必须使用bindItems
将表行(项)动态绑定到模型。 columns
聚合用于定义表的列布局,而items
聚合负责表记录。
在您的情况下,我将在控件定义中创建列,并使用您自己的模板将项绑定到模型。
这应该做你所期望的(测试它):
var oTable = new sap.m.Table("idRandomDataTable", {
headerToolbar : new sap.m.Toolbar({
content : [ new sap.m.Label({
text : "Summary Data"
}), new sap.m.ToolbarSpacer({}), new sap.m.Button("idPersonalizationButton", {
icon : "sap-icon://person-placeholder"
}) ]
}),
columns : [ new sap.m.Column({
width : "2em",
header : new sap.m.Label({
text : "Current Value"
})
}), new sap.m.Column({
width : "2em",
header : new sap.m.Label({
text : "Article"
})
}), new sap.m.Column({
width : "2em",
header : new sap.m.Label({
text : "Question"
})
}) ]
});
oTable.bindItems("/subvariants", new sap.m.ColumnListItem({
cells : [ new sap.m.Text({
text : "{currentValue}"
}), new sap.m.Text({
text : "{Article}"
}), new sap.m.Text({
text : "{question}",
}), ]
}));
oTable.setModel(new sap.ui.model.json.JSONModel(summaryDetailData));
希望这有助于你!