Question

好的，我在这里搞简单了。

我在一个活动中有三个类：

public class ActivityUserAccountCreate extends Activity implements
        OnClickListener {

}

private class postToHttps extends AsyncTask<String, Integer, String> {
@Override
    protected String doInBackground(String... params) {

        try {
            createUserAccount();

        } catch (ClientProtocolException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }

        return null;
    }
}

public void createUserAccount() throws ClientProtocolException, IOException {
...
ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();

Log.d("Posting Username", usernameFinal);
nameValuePairs.add(new BasicNameValuePair("username", "usernameFinal"));
...

}

在我的Activity类中，我初始化布局中的三个字符串。基本上用户在EditText中输入他们的用户名。字符串= =从字段中获取文本。一切正常，但我试图在createUserAccount（）中使用相同的字符串。我相信字符串在那时是空的，所以我必须在createUserAccount（）中再次重新初始化这三个相同的字符串吗？如果是这样，我应该像在Activity类中那样做吗？

由于

好的，我已根据以下建议编辑：

...
new postToHttps().execute(usernameFinal,passwordFinal,userEmail);
...

private class postToHttps extends AsyncTask<String, String, String> {

        @Override
        protected String doInBackground(String... params) {
        String usernameFinal = params[0];
            String passwordFinal = params[1];
            String userEmail = params[2];

            try {
                createUserAccount(usernameFinal, passwordFinal, userEmail);

            } catch (ClientProtocolException e) {
                e.printStackTrace();
            } catch (IOException e) {
                e.printStackTrace();
            }

            return null;
        }
    }

public void createUserAccount(String usernameFinal, String passwordFinal, String userEmail) throws ClientProtocolException, IOException {

    String uri = "editedout.php";
    Log.d("Action", "Posting user data to php");
    HttpClient client = new DefaultHttpClient();
    HttpPost getMethod = new HttpPost(uri);
    Log.d("Posting Location", uri);
    ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();

    Log.d("Posting Username", usernameFinal);
    nameValuePairs
            .add(new BasicNameValuePair("username", usernameFinal));

    Log.d("Posting Pass", passwordFinal);
    nameValuePairs
            .add(new BasicNameValuePair("password", passwordFinal));

    nameValuePairs.add(new BasicNameValuePair("email", userEmail));

    getMethod
            .setEntity(new UrlEncodedFormEntity(nameValuePairs, HTTP.UTF_8));
    client.execute(getMethod);
    Log.d("Action", "Finished Posting Data to PHP");
}

但是我遇到了崩溃。看起来它在doInBackground中崩溃了，但我还在学习读取LogCat。

Answer 1

您不必重新初始化任何内容，但如果您尝试将三个字符串传入AsyncTask，我建议您利用doInBackground(String... params)中使用的变量参数。

例如：

...
private class PostToHttps extends AsyncTask<String, Integer, String> {
@Override
    protected String doInBackground(String... params) {
        String username = params[0];
        String firstName = params[1];
        String lastName = params[2];

        createUserAccount(username, firstName, lastName);
    }
...

PostToHttps httpsTask = new PostToHttps();
httpsTask.execute(usernameEditText.getText().toString(),
                  firstNameEditText.getText().toString(),
                  lastNameEditText.getText().toString);

...

public void createUserAccount(String username, String firstName, String lastName)
    throws ClientProtocolException, IOException {
...

傻瓜的字符串初始化

1 个答案: