我对Python很陌生，所以我怀疑这个问题是由于天真而产生的，但任何帮助都会受到赞赏。
目前我有一个小型沿海演变模型。最初，这使用NumPy在一些约束内沿着定义的x轴随机生成100个点。代码的相关部分是：
# assign the number of points along the beach
Num_P_Coast = 100
# node spacing
dx = 10
x_vec = np.zeros(Num_P_Coast)
for i in range(0,Num_P_Coast):
x_vec[i] = dx*i
# initialize beach and cliff with random numbers
Bch_Width = np.random.uniform(0, 30, Num_P_Coast)
Cl_Loc = np.random.uniform(30, 60, Num_P_Coast)
然后，模型使用这两条初始线进行模型计算。我正在尝试做的是使用PyShp读取在ArcMap中绘制的折线来替换这些随机生成的点，然后将其用于模型计算。我正在尝试的代码是这样的：
BS1 = shp.Reader("Beach2.shp") #calling shapefile of beach front location
CL1 = shp.Reader("Cliff2.shp") #calling shapefile of cliff location
p1 = BS1.shapes()
b = p1[0]
BeachShp1 = b.points
p2 = CL1.shapes()
c = p2[0]
CliffShp1 = c.points
Bch_Width = np.random.uniform(0, 30, BS1) #Attempt to use polyline of beach to generate initial beach location
Cl_Loc = np.random.uniform(30, 60, CL1) #Attempt to use polyline of beach to generate initial beach location
当我在代码中尝试小的更改时，这会不断给出错误，例如“TypeError：需要一个整数”和“ValueError：序列太大;必须小于32”。
是否有人知道需要做什么才能让代码接受折线上的点，而不是随机生成的点？我觉得它应该很简单，但我已经在这里搜索了PyShp文档和其他问题，似乎无法找到该做什么。
干杯
完整代码：
def toy_beach_model(): #this is the main part of the program, which will call the evol_equations function to do all the jiggery pokery of outputting beach evolution
#where do you want to put it
#OutputDirectory = str(raw_input("Enter output directory:"))
OutputDirectory = 'c:/python_results/graphs/'
OutputModelName = eg.enterbox(title = 'Model name', msg = 'Enter model ID:')
ModelDesc = eg.enterbox(title = 'Model description', msg = 'Enter short description of model' )
# assign the number of points along the beach
Num_P_Coast = 100
# node spacing
dx = 10
x_vec = np.zeros(Num_P_Coast)
# some parameters
Cl_Eros_NoBch = int(eg.enterbox(title = 'Erosion rate', msg = 'Enter erosion rate:'))
Cl_Eros_HRock = Cl_Eros_NoBch * 0.5 #simulating harder rock = headland evolution
Cl_Eros_Efold = 50
Sup_Rate = int(eg.enterbox(title = 'Sediment supply', msg = 'Enter sediment supply rate:'))
K = 0.5
# set up x vector
for i in range(0,Num_P_Coast):
x_vec[i] = dx*i
BS1 = shp.Reader("Beach2.shp") #calling shapefile of beach front location
CL1 = shp.Reader("Cliff2.shp") #calling shapefile of cliff location
p1 = BS1.shapes()
b = p1[0]
BeachShp1 = b.points
p2 = CL1.shapes()
c = p2[0]
CliffShp1 = c.points
# initialize beach and cliff with random numbers
#Bch_Width = np.random.uniform(0, 30, Num_P_Coast)
#Cl_Loc = np.random.uniform(30, 60, Num_P_Coast)
Bch_Width = np.random.uniform(0, 30, BeachShp1) #Attempt to use polyline of beach to generate initial beach location
Cl_Loc = np.random.uniform(30, 60, CliffShp1) #Attempt to use polyline of beach to generate initial beach location
#H_Loc = Cl_Loc
#H_Loc = np.random.uniform(0, 8, Num_P_Coast)
H_Loc = np.random.random_sample(Num_P_Coast)
BcH_Eros = Bch_Width+Cl_Loc
# lets have this evolve through time
# time spacing in years
dt = 10
# number of time steps
n_timesteps = int(eg.enterbox(title = 'Timestep', msg = 'Enter number of iterations'))
# set up the beach erosion vector
Cl_Eros = np.zeros(Num_P_Coast)
H_Eros = np.zeros(Num_P_Coast)
# initial headland erosion
H_Eros = dt*Cl_Eros_HRock*np.exp(-Bch_Width/Cl_Eros_Efold)
# initial erosion
Cl_Eros = dt*Cl_Eros_NoBch*np.exp(-Bch_Width/Cl_Eros_Efold)
答案 0 :(得分：1)
错误是因为您正在尝试使用Bch_Width = np.random.uniform(0, 30, BeachShp1)等制作（可能）数千维数组。
numpy.random.uniform期望生成的数组的低，高和形状。
例如：
In [1]: import numpy as np
In [2]: np.random.uniform(0, 5) # Generate a single random number between 0 and 5
Out[2]: 4.149771995503083
In [3]: np.random.uniform(0, 5, 3) # Generate an array of three numbers
Out[3]: array([ 2.25725653, 0.70070352, 0.62541689])
In [4]: np.random.uniform(0, 5, (2,2)) # Generate a 2x2 array of 4 numbers
Out[4]:
array([[ 0.89355128, 3.30796407],
[ 1.23816971, 1.12224456]])
当你跑步时：
p1 = BS1.shapes()
b = p1[0]
BeachShp1 = b.points
BeachShp1是x，y坐标的序列。基本上，你正在尝试做类似的事情：
np.random.uniform(low, high, [[19.554, 45.998], [20.889, 24.009], ... ])
......这没有任何意义。
您是否尝试将随机海滩宽度添加到shapefile表示的行？或者计算悬崖轮廓和海滩轮廓之间的距离？或完全不同的东西？