Question

我有下面的字典词典，我必须使用这种格式，因为我没有权力超过服务器端

{"1":{"aov":0,"oo":1,"ot":"Cem-Merve","pi":87},"2":{"aov":100,"oo":2,"ot":"Murat-Pelin","pi":88},"3":{"aov":0,"oo":3,"ot":"Fevzi-Azbiye","pi":85},"4":{"aov":0,"oo":4,"ot":"Burak-Gizem","pi":86},"21":{"aov":100,"oo":21,"ot":"Murat","pi":84,"ro":2},"22":{"aov":0,"oo":22,"ot":"Pelin","pi":83,"ro":2}}

我需要按字母顺序用Javascript按键排序，就像

一样

{"1":{"aov":0,"oo":1,"ot":"Cem-Merve","pi":87},"2":{"aov":100,"oo":2,"ot":"Murat-Pelin","pi":88},"21":{"aov":100,"oo":21,"ot":"Murat","pi":84,"ro":2},"22":{"aov":0,"oo":22,"ot":"Pelin","pi":83,"ro":2},"3":{"aov":0,"oo":3,"ot":"Fevzi-Azbiye","pi":85},"4":{"aov":0,"oo":4,"ot":"Burak-Gizem","pi":86}}

我尝试了类似的东西，但没有希望：

function sortObject(o) {
    var sorted = {},
    key, a = [];

    for (key in o) {
        if (o.hasOwnProperty(key)) {
            a.push(key);
        }
    }

    a.sort();

    for (key = 0; key < a.length; key++) {
        sorted[a[key]] = o[a[key]];
    }
    return sorted;
}

任何想法我该怎么做？

Answer 1

正如其他人在评论中指出的那样，无法对对象的属性进行排序。您可以做的是生成对象属性的排序数组，并迭代该数组以按您希望的顺序访问对象属性。你基本上已经在你的示例代码中做了这个 - 你只是试着把它放得太远了。

See jsFiddle

function getObjectKeysAlphabetical(obj) {
    var keys = [],
        key;

    for (key in obj) {
        if (obj.hasOwnProperty(key))
            keys.push(key);
    }

    keys.sort();

    return keys;
}

var obj = {}; //Your object here.
var keys = getObjectKeysAlphabetical(obj)
    i = 0, key = null, val = null;

//Iterate the array of sorted keys.
for (i = 0; i < keys.length; i++) {
    key = keys[i];
    val = obj[key]; //Get the value of the property here.
}

按值按字母顺序排序字典的JSON字典

1 个答案: