Question

您好我有5个以上的mysql查询，我希望通过执行单个查询来查看所有查询的输出请让我知道如何加入所有这些疑问。

1

select sum(msu) 
from wgr_raw 
where dt 
between '2013-11-01' and '2013-11-07';

2

select * 
from wgr_raw 
where dt 
between '2013-11-01' and '2013-11-07' 
order by dt;

3。

select admin,sum(msu) 
from wgr_raw 
where dt 
between '2013-11-01' and '2013-11-07' 
group by admin;

4。

SELECT admin, sum(msu) 
from wgr_raw 
where dt 
between '2013-11-01' and '2013-11-07' 
group by admin 
order by msu desc 
limit 25; 

Select ADMIN1,WEEK1,WEEK2,WEEK3,
       (((WEEK3-WEEK2)/WEEK2)*100) as percentage_change, 
         (WEEK3-WEEK2) as MSU_Difference 
from 
       ((select admin as ADMIN1, sum(msu) as WEEK1 
         from wgr_raw 
         where dt >= date_sub(date('2013-11-01'), 
             INTERVAL 25 DAY) and dt < date_sub(date('2013-11-07'), 
             INTERVAL 18 DAY) 
         group by admin 
         order by WEEK1) as q1,
       (select admin as ADMIN2, sum(msu) as WEEK2 
        from wgr_raw 
        where dt >= date_sub(date('2013-11-01'), 
             INTERVAL 18 DAY) and dt < date_sub(date('2013-11-07'), 
             INTERVAL 11 DAY) 
         group by admin 
         order by WEEK2) as q2,
       (select admin as ADMIN3, sum(msu) as WEEK3 
        from wgr_raw where dt >= date_sub(date('2013-11-01'), 
             INTERVAL 11 DAY) and dt < date_sub(date('2013-11-07'), 
             INTERVAL 4 DAY) 
         group by admin 
         order by WEEK3) as q3)  
where ADMIN1=ADMIN3 and ADMIN2=ADMIN3 
group by admin1 
order by WEEK1 desc 
limit 25;

5。

select dt,sum(msu) 
from wgr_raw 
where dt >= date_sub(date('2013-11-01'), 
   INTERVAL 11 DAY) 
group by dt 
limit 7;

Answer 1

您可以使用UNION合并n个选择查询，但UNION中有一个条件。您的所有选择字段应该相同，并且排序依据。

(
    (SELECT a, b FROM tbl WHERE id >= 50 and id <= 100)
    UNION
    (SELECT a, b FROM tbl WHERE id >= 150 and id <= 200)
    UNION
    (SELECT a, b FROM tbl WHERE id >= 250 and id <= 300)
    UNION
    (SELECT a, b FROM tbl WHERE id >= 350 and id <= 400)

)
ORDER BY a

加入5个mysql查询

1 个答案: