我在使用PHP进行AES加密时会遇到一些问题,并使用C#对其进行解码。我的参考site。
这是PHP代码:
function encrypt_string($input, $key)
{
$iv = mcrypt_create_iv(mcrypt_get_iv_size(MCRYPT_RIJNDAEL_128, MCRYPT_MODE_CBC), MCRYPT_RAND);
return preg_replace('/=/', "", base64_encode($iv . mcrypt_encrypt(MCRYPT_RIJNDAEL_128, hash("sha256", $key, true), $input, MCRYPT_MODE_CBC, $iv)));
}
function decrypt_string($input, $key)
{
$input .= "=";
$data = base64_decode($input);
$iv = substr($data, 0, mcrypt_get_iv_size(MCRYPT_RIJNDAEL_128, MCRYPT_MODE_CBC));
return rtrim(mcrypt_decrypt(MCRYPT_RIJNDAEL_128,hash('sha256', $key, true),substr($data, mcrypt_get_iv_size(MCRYPT_RIJNDAEL_128, MCRYPT_MODE_CBC)),MCRYPT_MODE_CBC,$iv),"\0");
}
这是我尝试过的C#代码:
private static byte[] sha256_data(string input)
{
SHA256 hash = SHA256Managed.Create();
Encoding encode = Encoding.UTF8;
return hash.ComputeHash(encode.GetBytes(input));
}
private string encode_data(string data, string key)
{
byte[] buff;
RijndaelManaged rij = new RijndaelManaged();
rij.BlockSize = 256;
rij.KeySize = 256;
rij.GenerateIV();
rij.Key = sha256_data(key);
rij.Mode = CipherMode.CBC;
ICryptoTransform encoder = rij.CreateEncryptor(rij.Key, rij.IV);
using (MemoryStream mem = new MemoryStream())
{
using (CryptoStream crypt = new CryptoStream(mem, encoder, CryptoStreamMode.Write))
{
byte[] temp = Encoding.UTF8.GetBytes(data);
crypt.Write(temp, 0, temp.Length);
}
buff = mem.ToArray();
}
return Convert.ToBase64String(result);
}
private string decode_data(string input, string key)
{
RijndaelManaged rij = new RijndaelManaged();
rij.KeySize = 256;
rij.BlockSize = 256;
rij.Key = sha256_data(key);
rij.GenerateIV();
rij.Mode = CipherMode.CBC;
rij.Padding = PaddingMode.PKCS7;
ICryptoTransform decrypter = rij.CreateDecryptor();
byte[] buff;
using (MemoryStream mem = new MemoryStream())
{
using (CryptoStream cstream = new CryptoStream(mem, decrypter, CryptoStreamMode.Write))
{
byte[] data = Convert.FromBase64String(input);
cstream.Write(data, 0, data.Length);
}
buff = mem.ToArray();
}
return Encoding.UTF8.GetString(buff);
}
我做错了什么?
答案 0 :(得分:0)
解码时,必须解析用于编码的IV而不生成新的。