Question

我有一个临时表，它是以前重组合数据的结果，我必须创建html文档才能显示。

此表简要说明了情况：

DROP TABLE IF EXISTS temp11;
CREATE TABLE temp11 (t_idx int PRIMARY KEY, mydate text, myclass int, mypercent double precision, valpercent double precision, valclass double precision);

INSERT INTO temp11
(t_idx, mydate, myclass, mypercent, valpercent, valclass) VALUES 
(1,  '01.01.2014',  1,  10,      10,      1),
(2,  '01.01.2014',  2,  20,      20,      4),
(3,  '01.01.2014',  2,  20,      50,     10),
(4,  '01.01.2014',  1,  10,      17,    1.7),
(5,  '02.01.2014',  2,  20,      40,      8),
(6,  '02.01.2014',  1,  10,      18,    1.8),
(7,  '02.01.2014',  2,  20,      50,     10),
(8,  '03.01.2014',  1,  10,      10,      1),
(9,  '03.01.2014',  2,  20,      40,      8),
(10, '03.01.2014',  1,  10,      20,      2),
(11, '03.01.2014',  2,  20,      30,      6);

现在我有一个查询，将其分组并汇总到日期和valclasses中：

SELECT mydate, myclass, mypercent, 
      SUM(valpercent)          AS sumvalpercent, 
      SUM(valclass)            AS sumvalclass, 
      SUM(valpercent+valclass) AS sum_row 
FROM  temp11 
GROUP BY mydate, myclass, mypercent 
ORDER BY mydate;

此查询的结果是可以预期的：

"01.01.2014"   2   20   70  14.0   84.0
"01.01.2014"   1   10   27   2.7   29.7
"02.01.2014"   1   10   18   1.8   19.8
"02.01.2014"   2   20   90  18.0  108.0
"03.01.2014"   2   20   70  14.0   84.0
"03.01.2014"   1   10   30   3.0   33.0

但需求有点延长。

是否可以使用PostgreSQL，在每个日期之后的同一过程中，我在该日期内获得数据的垂直SUM，毕竟，最后，来自所有日期的数据的SUM将如下所示：

"01.01.2014"   2   20   70  14.0   84.0
"01.01.2014"   1   10   27   2.7   29.7
                        97  16.7  113.7
"02.01.2014"   1   10   18   1.8   19.8
"02.01.2014"   2   20   90  18.0  108.0
                       108  19.8  127.8
"03.01.2014"   2   20   70  14.0   84.0
"03.01.2014"   1   10   30   3.0   33.0
                       100  17.0  117.0
                       305  53.5  358.5

如果可能这样（或类似），那么查询应该如何显示数据？

Answer 1

我能想到的最简单的方法是使用UNION ALL一次获得所有想要的输出。如果省略显示日期的事实（order by子句需要），则此查询以最简单的方式提供请求的输出。

SELECT mydate, myclass, mypercent, 
      SUM(valpercent)          AS sumvalpercent, 
      SUM(valclass)            AS sumvalclass, 
      SUM(valpercent+valclass) AS sum_row 
FROM  temp11 
GROUP BY mydate, myclass, mypercent 
UNION ALL
SELECT mydate || ' total', null, null, 
      SUM(valpercent)          AS sumvalpercent, 
      SUM(valclass)            AS sumvalclass, 
      SUM(valpercent+valclass) AS sum_row 
FROM  temp11 
GROUP BY mydate
UNION ALL
SELECT 'Total', null, null, 
      SUM(valpercent)          AS sumvalpercent, 
      SUM(valclass)            AS sumvalclass, 
      SUM(valpercent+valclass) AS sum_row 
FROM  temp11 
ORDER BY mydate;

这是fiddle

也许可以使用WITH

更优雅地重写它

修改

这将更有效，因为它只遍历temp11表一次。然后它只使用临时表temp100，其中额外总数少得多（每天不超过一行）。 UNION仍然存在且逻辑仍然相同。

WITH temp100 (mydate,myclass,mypercent, sumvalpercent,sumvalclass,sum_row) as ( SELECT mydate, myclass, mypercent, SUM(valpercent) AS sumvalpercent, SUM(valclass) AS sumvalclass, SUM(valpercent+valclass) AS sum_row FROM temp11 GROUP BY mydate, myclass, mypercent ) SELECT mydate,myclass,mypercent, sumvalpercent,sumvalclass,sum_row FROM temp100 UNION ALL SELECT mydate || ' total' as mydate, null, null, SUM(sumvalpercent), SUM(sumvalclass), SUM(sum_row) FROM temp100 GROUP BY mydate UNION ALL SELECT 'Total' as mydate, null, null, SUM(sumvalpercent), SUM(sumvalclass), SUM(sum_row) FROM temp100 ORDER BY mydate;

这是fiddle

PostgreSQL，水平和垂直混合SUM

1 个答案: