Question

以下是我的代码..

while(obt.hasNext()){

        try{
            Object itrvalue = obt.next();
            String sql2 ="select entryDt,Student_Name,Class_Div_Name,ReceiptNo from       test where ReceiptNo = '"+itrvalue+"'";
            System.out.println("Receipt No --"+itrvalue);
            stat =  con.prepareStatement(sql2);
            rs=stat.executeQuery();
            rs.next();
            Date datevalue = rs.getDate(1);
            String name = rs.getString(2);
            String CDN = rs.getString(3);
            String RNO = rs.getString(4);
            System.out.println("Date is ---"+datevalue);
            System.out.println("Student Name ---"+name);
            System.out.println("Coloumn Div No ---"+CDN);
            System.out.println("Receipt No ---"+RNO);
            rs.close();
            }
            catch(Exception ex){};
        }

输出： -

Receipt No  --S00000001234
Date is ---2013-06-10 
Student Name ---ABC XYZ 
Coloumn Div No ---VI - C 
Receipt No ---S00000001234
Receipt No --S00000001234 
Receipt No --S00000001235
Receipt No --S00000001236
Receipt No --S00000001237 
Receipt No --S00000001238
Receipt No --S00000001239

每个迭代值都会发生变化。但是在当前的SQL查询中，它只是传递了第一个值剩余的迭代值，但是没有在SQL查询中传递。根据输出，您可以看到我只收到了数据S00000001234，我想要所有收据号的相同详细信息。

Answer 1

您可能已经提出异常。请尝试使用此代码：

String sql2 = "select entryDt,Student_Name,Class_Div_Name,ReceiptNo from test where ReceiptNo = ?";
PreparedStatement stat = con.prepareStatement(sql2);

try {
    while (obt.hasNext()) {
        try {
            Object itrvalue = obt.next();
            System.out.println("Receipt No --" + itrvalue);
            stat.setObject(1, itrvalue);
            rs = stat.executeQuery();
            rs.next();
            Date datevalue = rs.getDate(1);
            String name = rs.getString(2);
            String CDN = rs.getString(3);
            String RNO = rs.getString(4);
            System.out.println("Date is ---" + datevalue);
            System.out.println("Student Name ---" + name);
            System.out.println("Coloumn Div No ---" + CDN);
            System.out.println("Receipt No ---" + RNO);
            rs.close();
        } catch (Exception ex) {
            ex.printStackTrace();
        }
    }
} finally {
    if (stat != null) {
        stat.close();
    }
}

在传递的Query中没有迭代收集值？

1 个答案: