Question

我已经通过ajax post将数组从jquery传递到php处理脚本。我注意到我在php中的foreach迭代没有做任何事情。我添加了一个vat_dump，并意识到我为这个数组得到了奇怪的结果。为什么会在值中附加字符串（x）？我相信这就是我的循环运行不正常的原因。

我对php中的数组非常熟悉，但就将jquery传递给php并使用它们而言，我从来没有遇到类似这样的事情。

$('#delete').on('click', function () {

    var selected = [0, 1, 2, 3, 4, 5];
    var data = {
      'selected': selected
    };

    $.ajax({
        type: 'post',
        url: '/process/p_delete.php',
        data: data,
        dataType : 'json'
    }).done(function (response) {

        if (response.success)
        {                                                                                               
            // show success toast
            toastr.info('Selected activities have been deleted from your account.');                        
        } 
        else
        {
            // show error toast
            toastr.error('An error has occurred. &nbsp;Please contact support.', 'Error');
        }

    });
});

然后在php：

$selected = $_POST['selected'];
var_dump($selected);

// prepare the statement
$stmt = $db->prepare("DELETE FROM logs WHERE activity_id = ? AND account_id = ?");

//loop through array and delete each selected
foreach($selected as $key)
{
    $binding = array(
    'account_id' => $_SESSION['user']['account_id'],
    'activity_id' => $key
    );

    // execute the delete
    $stmt->execute($binding);
}

转储结果如下：

array(6) {
  [0]=>
  string(1) "0"
  [1]=>
  string(1) "1"
  [2]=>
  string(1) "2"
  [3]=>
  string(1) "3"
  [4]=>
  string(1) "4"
  [5]=>
  string(1) "5"
}

Answer 1

尝试

$stmt->execute(array($key, $_SESSION['user']['account_id']));

或使用命名参数（参见http://php.net/manual/en/pdostatement.execute.php）。而不是进行多次查询，最好只使用一个查询使用WHERE IN -clause。

Answer 2

我不是PHP的专家，但我会尝试这样：

<强> JAVASCRIPT

var selected = [0, 1, 2, 3, 4, 5];
var jsonObj = JSON.stringify(selected);//encode array to JSON format
var data = {
  'selected': jsonObj
};

<强> PHP

  $data = json_decode(stripslashes($_POST['selected']));//decode json to array
  foreach($data as $value){
     echo $value;
  }

Answer 3

试试这个

$sth = $dbh->prepare('DELETE FROM logs WHERE activity_id = :activityId AND account_id = :accountId');

//loop through array and delete each selected
foreach($selected as $key)
{
    $sth->bindParam(':activityId', $_SESSION['user']['account_id'], PDO::PARAM_INT);
    $sth->bindParam(':accountId', $key, PDO::PARAM_INT);
    $sth->execute();
}

如果你得到$_SESSION['user']['account_id']和$key，那么它就可以了。还检查pdo数据库连接和列名和表名

Answer 4

doh ...我想这就是我累得太累了......

$stmt = $db->prepare("DELETE FROM logs WHERE activity_id = :activity_id AND account_id = :account_id");

我从我的代码的另一部分复制了我的语句，我直接将值插入到此语句中。在这一个我绑定他们...因此，=？在这种情况下并不好。

传递给php的jquery数组给出了意想不到的格式

4 个答案: