Question

for(int i=0; i<arrString.count;i++){
if([[arrString objectAtIndex:i] rangeOfString:@"www."].location != NSNotFound)
    link = [arrString objectAtIndex:i];
}


NSString *url = (@"THIS IS WHERE HTTP:// would Be!%@", link);
    NSLog(@"THIS IS WHERE HTTP:// would Be!%@", url);
NSURL *nsurl=[NSURL URLWithString:url];
NSURLRequest *nsrequest=[NSURLRequest requestWithURL:nsurl];
[_webView1 loadRequest:nsrequest];

当我使用NSLog时：

NSLog(@"THIS IS WHERE HTTP:// would Be!, url);

它记录以http://.开头的正确URL但是，当我将字符串URL设置为http://"link"时，它不会返回任何内容。任何帮助深表感谢。

（Stack Overflow不让我把真正的HTTP：//后跟％@。）

Answer 1

看起来您可能需要使用stringWithFormat:

NSString *domainName = @"aol.com";
NSString *url = [NSString stringWithFormat:@"http://www.%@", domainName];

UIWebView无法打开链接

1 个答案: