Question

例如

NSString *string = @"I need help finding a string";
NSString *newString = @"need";

我需要这个不仅适用于此字符串。一个例子是取一个字符串并删除单词“I”之后和单词“help”之前的所有内容。非常感谢你！

从评论中删除易读性：

NSString *string = @"I need help finding a string";
NSRange rr2 = [TWEET rangeOfString:@"I "];
NSRange rr3 = [TWEET rangeOfString:@" help"];
int lengt = rr3.location - rr2.location;
int location = rr2.location + rr2.length;
NSRange aa;
aa.location = location;
aa.length = lengt;
NSString *link;
link = [TWEET substringWithRange:aa];
NSLog(@"The link is %@", link);

Answer 1

一种方法是将字符串拆分成单个单词，然后迭代它，首先搜索第一个单词，同时将每个单词添加到新字符串，直到找到它并搜索第二个单词并在找到之后只是添加剩余的单词。

在代码中看起来像这样：

    NSString *myString = @"I need help finding a string";

    NSString *firstWord = @"need";

    NSString *secondWord = @"a";

    NSMutableString *newString = [NSMutableString stringWithString:@""];

    int index = 0;

    for (NSString *word in [myString componentsSeparatedByString:@" "]) {
        if(index == 0) {
            if([word isEqualToString:firstWord])
                index = 1;
            [newString appendFormat:@"%@ ", word];
        }
        else if(index == 1) {
            if([word isEqualToString:secondWord])
                index = 2;
        }
        else
            [newString appendFormat:@"%@ ", word];

     }

我怎样才能找到一个单词，并在第一次出现单词后取出所有字符，但在出现不同单词后停止？

1 个答案: