Question

我正在尝试创建一个包含2个edittexts的对话框来创建密码。这是我的代码：

AlertDialog.Builder alert = new AlertDialog.Builder(this);
            alert.setCancelable(false);
            alert.setTitle(title);
            alert.setMessage(message);
            LayoutInflater layoutInflater = (LayoutInflater) this.getSystemService(LAYOUT_INFLATER_SERVICE);
            LinearLayout layout = (LinearLayout) layoutInflater.inflate(R.layout.create_pass, null);
            final EditText password = (EditText) layout.findViewById(R.id.password);
            final EditText passconfirm = (EditText) layout.findViewById(R.id.repeat_password);
            password.setMinEms(6);
            alert.setView(layout);
            alert.setPositiveButton(R.string.ok, new DialogInterface.OnClickListener() {
                public void onClick(DialogInterface dialog, int whichButton) {
                    if (!password.getText().toString().equals(passconfirm.getText().toString())) {
                        passconfirm.setError(getString(R.string.password_mismatch));
                        return;
                    } else if (password.getText().toString().isEmpty()) {
                        password.setError(getString(R.string.password_empty));
                        return;
                    } else {
                        secprefs.putString("master_password", password.getText().toString());
                    }
                }
            });
            alert.setNegativeButton(getString(R.string.cancel), new DialogInterface.OnClickListener() {
                public void onClick(DialogInterface dialog, int whichButton) {
                    dialog.cancel();
                }
            });

            alert.show();

对话框工作正常，如果遵守2个条件，则存储密码。现在，如果不满足2个条件，则对话框将自行关闭。我想使对话框关闭并显示小弹出错误。谁知道为什么？

我想设置的另外一件事是密码的最小长度。我尝试使用setMinEms（6），但它无法正常工作。

由于

Answer 1

嗯，这就是我为进一步相关问题解决的问题：

       AlertDialog.Builder alert = new AlertDialog.Builder(this);
        alert.setCancelable(false);
        alert.setTitle(getString(R.string.dlgtitle));
        alert.setMessage(getString(R.string.dlgmessage));
        LayoutInflater layoutInflater = (LayoutInflater) this.getSystemService(LAYOUT_INFLATER_SERVICE);
        LinearLayout layout = (LinearLayout) layoutInflater.inflate(R.layout.pass_create, null);
        final EditText password = (EditText) layout.findViewById(R.id.password);
        final EditText passconfirm = (EditText) layout.findViewById(R.id.repeat_password);
        password.setMinEms(6);
        alert.setView(layout);
        alert.setPositiveButton(R.string.ok, null);
        alert.setNegativeButton(getString(R.string.cancel), new DialogInterface.OnClickListener() {
            public void onClick(DialogInterface dialog, int whichButton) {
                dialog.cancel();
            }
        });

        final AlertDialog dialog = alert.create();
        dialog.setOnShowListener(new DialogInterface.OnShowListener() {
            @Override
            public void onShow(DialogInterface dialogInterface) {
                Button ok = dialog.getButton(AlertDialog.BUTTON_POSITIVE);
                if (ok != null) {
                    ok.setOnClickListener(new View.OnClickListener() {
                        @Override
                        public void onClick(View view) {
                            if (!password.getText().toString().equals(passconfirm.getText().toString())) {
                                password.setError(getString(R.string.password_mismatch));
                            } else if (password.getText().toString().length() <= 6) {
                                password.setError(getString(R.string.pass_lenght));
                            } else if (password.getText().toString().isEmpty()) {
                                password.setError(getString(R.string.password_empty));
                            } else {
                                secprefs.putBoolean("first_step", false);
                                secprefs.putString("master_password", password.getText().toString());
                                dialog.cancel();
                            }
                        }
                    });
                }
            }
        });
        dialog.show();

Answer 2

可以使用这样的模式检查密码的最小长度...示例

password.getText().toString().matches("[a-zA-Z0-9_]{6,}")

关于在输入中显示错误消息，您可以像这个示例一样使用Toast ......

Toast.makeText(this, "Input error!!!", Toast.LENGTH_LONG).show();

比较2个EditText条目并在Android中显示对话框中的错误

2 个答案: