我正在使用LIBSVM以编程方式进行简单的XOR分类,试图了解这些函数的工作原理。我已按照自述文件中的说明尽可能地设置了问题。使用svm_predict时总是得到错误的输出(总是1或-1)。
在一个相关问题中,有人建议在使用极少数训练样例时可能会出现问题。我尝试将示例数量增加到20但这没有帮助。
我怀疑问题是在prob.x和/或prob.y的定义中的某处,但无法理解在哪里。您能否帮助阐明如何使用svm_node定义prob.x和prob.y?
我彻底搜查但找不到答案......例如Here, here, here, here, and here.
提前致谢!
这是我的代码:
//Parameters
svm_parameter param;
param.svm_type = C_SVC;
param.kernel_type = RBF;
param.degree = 3;
param.gamma = 0;
param.coef0 = 0;
param.nu = 0.5;
param.cache_size = 100;
param.C = 0.4;
param.eps = 1e-3;
param.p = 0.1;
param.shrinking = 1;
param.probability = 0;
param.nr_weight = 0;
param.weight_label = NULL;
param.weight = NULL;
//Problem definition
svm_problem prob;
//Length
prob.l = 4; //number of training examples
//x values
svm_node** x = new svm_node *[prob.l]; //Array of pointers to pointers to arrays
svm_node* x_space1 = new svm_node[3]; //Fist training example
svm_node* x_space2 = new svm_node[3]; //Second training example
svm_node* x_space3 = new svm_node[3]; //Third training example
svm_node* x_space4 = new svm_node[3]; //Fourth training example
x_space1[0].index = 1; //Fist training example
x_space1[0].value = 1;
x_space1[1].index = 2;
x_space1[1].value = 1;
x_space1[2].index = -1;
x_space2[0].index = 1; //Second training example
x_space2[0].value = 1;
x_space2[1].index = 2;
x_space2[1].value = 0;
x_space2[2].index = -1;
x_space3[0].index = 1; //Third training example
x_space3[0].value = 0;
x_space3[1].index = 2;
x_space3[1].value = 1;
x_space3[2].index = -1;
x_space4[0].index = 1; //Fourth training example
x_space4[0].value = 0;
x_space4[1].index = 2;
x_space4[1].value = 0;
x_space4[2].index = -1;
x[0] = x_space1; //Set each training example to x
x[1] = x_space2;
x[2] = x_space3;
x[3] = x_space4;
prob.x = x; //Assign x to the struct field prob.x
//yvalues
prob.y = new double[prob.l];
prob.y[0] = -1;
prob.y[1] = 1;
prob.y[2] = 1;
prob.y[3] = -1;
//Train model
svm_model *model = svm_train(&prob,¶m);
//Test model
svm_node* testnode = new svm_node[3];
testnode[0].index = 1;
testnode[0].value = 1;
testnode[1].index = 2;
testnode[1].value = 0;
testnode[2].index = -1;
double retval = svm_predict(model,testnode);
qDebug()<<retval; //Should return +1 but returns -1
答案 0 :(得分:1)
C
参数看起来很可疑(0.4
可能会变低,尝试1000
)答案 1 :(得分:1)
您的参数似乎有问题。例如,如果您使用RBF内核,则param.gamma不应为零。