SharePoint 2013使用JavaScript获取当前用户

Question

如何在脚本编辑器Web部件中使用JavaScript获取当前用户名？

Answer 1

以下代码对我有用：

<script src="/SiteAssets/jquery.SPServices-2013.02a.js" type="text/javascript"></script>
<script src="/SiteAssets/jquery.js" type="text/javascript"></script>

<script type="text/javascript">
  var userid= _spPageContextInfo.userId;
  var requestUri = _spPageContextInfo.webAbsoluteUrl + "/_api/web/getuserbyid(" + userid + ")";
  var requestHeaders = { "accept" : "application/json;odata=verbose" };
  $.ajax({
    url : requestUri,
    contentType : "application/json;odata=verbose",
    headers : requestHeaders,
    success : onSuccess,
    error : onError
  });

  function onSuccess(data, request){
    var loginName = data.d.Title;
    alert(loginName);
  }

  function onError(error) {
    alert("error");
  }
</script>

Answer 2

我找到了一种更简单的方法，它甚至不使用SP.UserProfiles.js。我不知道它是否适用于每个人的特定情况，但绝对值得分享。

//assume we have a client context called context.
var web = context.get_web();
var user = web.get_currentUser(); //must load this to access info.
context.load(user);
context.executeQueryAsync(function(){
    alert("User is: " + user.get_title()); //there is also id, email, so this is pretty useful.
}, function(){alert(":(");});

无论如何，多亏了你的回答，我得与UserProfiles混在一起，尽管我的情况并非真的有必要。

Answer 3

这个怎么样：

$.getJSON(_spPageContextInfo.webServerRelativeUrl + "/_api/web/currentuser")
.done(function(data){ 
    console.log(data.Title);
})
.fail(function() { console.log("Failed")});

Answer 4

如果您在SharePoint页面中，请使用：

_spPageContextInfo.userId;

Answer 5

您可以使用SharePoint JSOM获取当前用户的帐户信息。此代码（当作为脚本编辑器Web部件中的片段添加时）将在浏览器中弹出用户的显示和帐户名称 - 您将要添加gotAccount中的任何其他内容以获取格式中的名称你想要的。

<script type="text/javascript" src="/_layouts/15/SP.js"></script>
<script type="text/javascript" src="/_layouts/15/SP.UserProfiles.js"></script>
<script type="text/javascript">

  var personProperties;

  SP.SOD.executeOrDelayUntilScriptLoaded(getCurrentUser, 'SP.UserProfiles.js');

  function getCurrentUser() {
    var clientContext = new SP.ClientContext.get_current();
    personProperties = new SP.UserProfiles.PeopleManager(clientContext).getMyProperties();
    clientContext.load(personProperties);
    clientContext.executeQueryAsync(gotAccount, requestFailed);
  }

  function gotAccount(sender, args) {
    alert("Display Name: "+ personProperties.get_displayName() + 
        ", Account Name: " + personProperties.get_accountName());
  }

  function requestFailed(sender, args) {
    alert('Cannot get user account information: ' + args.get_message());
  }

</script>

有关详细信息，请参阅MSDN中的SP.UserProfiles.PersonProperties文档。

Answer 6

获取当前用户信息：

jQuery.ajax({
    url: _spPageContextInfo.webServerRelativeUrl + "/_api/web/currentuser",
    type: "GET",
    headers: { "Accept": "application/json;odata=verbose" }
}).done(function( data ){
    console.log( data );
    console.log( data.d.Title );
}).fail(function(){
    console.log( failed );
});

Answer 7

你可以使用javascript来达到这个目的：

function loadConstants() {

    this.clientContext = new SP.ClientContext.get_current();
    this.clientContext = new SP.ClientContext.get_current();
    this.oWeb = clientContext.get_web();
    currentUser = this.oWeb.get_currentUser();  
    this.clientContext.load(currentUser);
      completefunc:this.clientContext.executeQueryAsync(Function.createDelegate(this,this.onQuerySucceeded), Function.createDelegate(this,this.onQueryFailed));


}

//U must set a timeout to recivie the exactly user u want:

function onQuerySucceeded(sender, args) {

    window.setTimeout("ttt();",1000);
}
function onQueryFailed(sender, args) {

    console.log(args.get_message());
}

//By using a proper timeout, u can get current user :

function ttt(){ 

    var clientContext = new SP.ClientContext.get_current();
    var groupCollection = clientContext.get_web().get_siteGroups();
    visitorsGroup = groupCollection.getByName('OLAP Portal Members');

    t=this.currentUser .get_loginName().toLowerCase();

    console.log ('this.currentUser .get_loginName() : '+ t);      

}

Answer 8

我必须使用XML进行此操作，通过添加内容编辑器Web部件将以下内容放入内容编辑器Web部件中，编辑Web部件，然后单击“编辑源代码”按钮并粘贴到其中：

ORA-00906: missing left parenthesis
00906. 00000 -  "missing left parenthesis"
*Cause:    
*Action:
Error at Line: 11 Column: 38

检查以下链接以查看您的数据是XML还是JSON：

  

https://<Your_Sharepoint_Domain>/_api/web/currentuser

在接受的答案中，凯特（Kate）使用以下方法：

SELECT a.BG_BUG_ID as "Defect-Id",
a.BG_SEVERITY as "Severity",
a.BG_STATUS as "Status",
a.BG_SUMMARY as "Summary",
a.BG_DETECTION_DATE as "Detected on Date",
a.BG_USER_05 as "Resolution",
a.BG_USER_01 as"Product",
a.BG_DETECTION_VERSION as "Detected in Version",
CAST(CASE
 WHEN b.TS_TEST_ID IS NOT NULL
    THEN CAST(b.TS_TEST_ID AS varchar)
 ELSE "N/A"
END AS varchar) as "Test-Id",
CAST(CASE
 WHEN c.RN_RUN_ID IS NOT NULL
    THEN CAST(c.RN_RUN_ID AS varchar)
 ELSE "N/A"
END AS varchar) as "Run-Id",
CAST(CASE
 WHEN d.TC_TESTCYCL_ID IS NOT NULL
    THEN CAST(d.TC_TESTCYCL_ID AS varchar)
 ELSE "N/A"
END AS varchar) as "Test-Instance-Id",
CAST(CASE
 WHEN e.BG_BUG_ID IS NOT NULL
    THEN CAST(e.BG_BUG_ID AS varchar)
 ELSE "N/A"
END AS varchar) as "Linked-Defect-Id", -- there is no need for this ID. You have it in the first selected coulmn
CAST(CASE
 WHEN f.ST_ID IS NOT NULL
    THEN CAST(f.ST_ID AS varchar)
 ELSE "N/A"
END AS varchar) as "TestStep-Id",
CAST(CASE
 WHEN g.CY_CYCLE_ID IS NOT NULL
    THEN CAST(g.CY_CYCLE_ID AS varchar)
 ELSE "N/A"
END AS varchar) as "Test-Set-Id",
CAST(CASE
 WHEN h.RQ_REQ_ID IS NOT NULL
    THEN CAST(h.RQ_REQ_ID AS varchar)
 ELSE "N/A"
END AS varchar) as "Requirement-Id(Direct Link)",
CAST(CASE
 WHEN i.RC_REQ_ID IS NOT NULL
    THEN CAST(i.RC_REQ_ID AS varchar)
 ELSE "N/A"
END AS varchar) as "Requirement-Id(Coverage Link)"
FROM
BUG a
FULL JOIN LINK l ON (a.BG_BUG_ID = l.LN_BUG_ID AND l.LN_ENTITY_TYPE IN ("TEST","RUN","TESTCYCL","BUG","STEP","CYCLE", "REQ"))
LEFT JOIN TEST b ON (l.LN_ENTITY_ID = b.TS_TEST_ID AND l.LN_ENTITY_TYPE = "TEST")
LEFT JOIN RUN c ON (l.LN_ENTITY_ID = c.RN_RUN_ID AND l.LN_ENTITY_TYPE = "RUN")
LEFT JOIN TESTCYCL d ON (l.LN_ENTITY_ID = d.TC_TESTCYCL_ID AND l.LN_ENTITY_TYPE = "TESTCYCL")
LEFT JOIN BUG e ON (l.LN_ENTITY_ID = e.BG_BUG_ID AND l.LN_ENTITY_TYPE = "BUG")
LEFT JOIN STEP f ON (l.LN_ENTITY_ID = f.ST_ID AND l.LN_ENTITY_TYPE = "STEP")
LEFT JOIN CYCLE g ON (l.LN_ENTITY_ID = g.CY_CYCLE_ID AND l.LN_ENTITY_TYPE = "CYCLE")
LEFT JOIN REQ h ON (l.LN_ENTITY_ID = h.RQ_REQ_ID AND l.LN_ENTITY_TYPE = "REQ")
LEFT JOIN REQ_COVER i ON (i.RC_ENTITY_ID = b.TS_TEST_ID AND i.RC_ENTITY_TYPE="TEST")

Answer 9

如果您知道用户的ID，则可以使用以下功能：

function getUser(id){
var returnValue;
jQuery.ajax({
 url: "http://YourSite/_api/Web/GetUserById(" + id + ")",
 type: "GET",
 headers: { "Accept": "application/json;odata=verbose" },
 success: function(data) {
       var dataResults = data.d;
       alert(dataResults.Title);
  }
});
}

或者你可以尝试

var listURL = _spPageContextInfo.webAbsoluteUrl + "/_api/web/currentuser";

Answer 10

试试这段代码..

function GetCurrentUsers() {

    var context = new SP.ClientContext.get_current();
    this.website = context.get_web();
    var currentUser = website.get_currentUser();
    context.load(currentUser);
    context.executeQueryAsync(Function.createDelegate(this, onQuerySucceeded), Function.createDelegate(this, onQueryFailed));
   function onQuerySucceeded() {

       var currentUsers = currentUser.get_title();
       document.getElementById("txtIssued").innerHTML = currentUsers;

    }

    function onQueryFailed(sender, args) {
        alert('request failed ' + args.get_message() + '\n' + args.get_stackTrace());
    }   

}

Answer 11

您可以使用sp页面的上下文信息：

_spPageContextOnfo.userLoginName