Question

我有以下非常简单的应用程序：

from lib.flask import Flask

from lib.flask_restful import Resource, Api

app = Flask(__name__)
api = Api(app)


class TestResource(Resource):
    def get(self):
        return {"a":"b","c":"d"}
api.add_resource(TestResource, "/")

当我运行它时，我得到以下异常：

Traceback (most recent call last):
  File "/Applications/GoogleAppEngineLauncher.app/Contents/Resources/GoogleAppEngine-default.bundle/Contents/Resources/google_appengine/google/appengine/runtime/wsgi.py", line 266, in Handle
    result = handler(dict(self._environ), self._StartResponse)
  File "/Users/me/dev/project/src/main.py", line 22, in do_in_request
    app(*args, **kwargs)
  File "/Users/me/dev/project/src/lib/flask/app.py", line 1836, in __call__
    return self.wsgi_app(environ, start_response)
  File "/Users/me/dev/project/src/lib/flask/app.py", line 1820, in wsgi_app
    response = self.make_response(self.handle_exception(e))
  File "/Users/me/dev/project/src/lib/flask_restful/__init__.py", line 249, in error_router
    if self._has_fr_route():
  File "/Users/me/dev/project/src/lib/flask_restful/__init__.py", line 230, in _has_fr_route
    if self._should_use_fr_error_handler():
  File "/Users/me/dev/project/src/lib/flask_restful/__init__.py", line 211, in _should_use_fr_error_handler
    adapter = self.app.create_url_adapter(request)
  File "/Users/me/dev/project/src/lib/flask/app.py", line 1601, in create_url_adapter
    return self.url_map.bind_to_environ(request.environ,
  File "/Users/me/dev/project/src/lib/werkzeug/local.py", line 338, in __getattr__
    return getattr(self._get_current_object(), name)
  File "/Users/me/dev/project/src/lib/werkzeug/local.py", line 297, in _get_current_object
    return self.__local()
  File "/Users/me/dev/project/src/lib/flask/globals.py", line 20, in _lookup_req_object
    raise RuntimeError('working outside of request context')
RuntimeError: working outside of request context

所以我试着把我的整个应用程序放到我认为的请求上下文中。在上面的代码中，Flask对象和Api对象都被实例化一次，并且可以由服务器多次调用。从回溯中看，实例化应该在请求上下文中发生，所以我把它包装成这样：

def do_in_request(*args, **kwargs):
    from lib.flask import Flask

    from lib.flask_restful import Resource, Api

    app = Flask(__name__)
    api = Api(app)


    class TestResource(Resource):
        def get(self):
            return {"a":"b","c":"d"}
    api.add_resource(TestResource, "/")

    app(*args, **kwargs)

app = do_in_request

仍然会引发同样的错误。发生了什么，“请求上下文”是什么意思，我该如何解决？

Answer 1

我从头开始使用App Engine Flask Skeleton并在flask-restful中添加了requirements.txt作为依赖项，然后只添加了或多或少的上面代码，并且它没有问题。我将存储库添加到my github here，如果您想使用它 - 您可以在this commit中看到我对骨架所做的更改。

我不确定为什么你的例子不起作用，但有一点我注意到可能导致问题的是你正在做from lib.flask ...。您的第三方软件包似乎存在于lib中，并且您无法提升并且＃34; lib sys.path。骨架包含vendoring library，以确保正确处理。这可能是问题的潜在根源。

无论哪种方式，我希望分叉的骨架可以帮助你起床和跑步。

在Google App Engine上运行简单的flask_restful应用程序时出现RuntimeError

1 个答案: