Question

我在cassandra表中插入一组数据。但是我在那里得到了不匹配的列名/值。我发布了代码以及表结构

public static void aMethod2FromData(DetailsVO detailsVO) {

    System.out.println(detailsVO.getA_no());

    StringBuilder sb = new StringBuilder();

    int num = (int) (Math.random() * 8847);
    int radar = (int) (Math.random() * 847);
    sb.append(
    "INSERT INTO CALL_RATIO_ANALYSYS (A_NO,JAN,FEB,MAR,APR,MAY,JUNE,JULY,AUG,SEP,OCT,NOV,DEC,RADAR_VOICE,RADAR_SMS,RADAR_MMS,RADAR_GPRS,RADAR_OTHER,MMS_INCOMING,MMS_OUTGOING,VOICE_INCOING,VOICE_OUTGOING,SMS_INCOMING,SMS_OUTGOING,GPRS_SOCIAL,GPRS_MAIL,GPRS_GOOGLE,GPRS_ENTERTAINMENT,GPRS_BUSINESS)")
            .append("VALUES(");



        sb.append("'").append(detailsVO.getA_no()).append("',");
        //calculation for Jan to dec
        sb.append("'").append(num).append("',");
        sb.append("'").append(num).append("',");
        sb.append("'").append(num).append("',");
        sb.append("'").append(num).append("',");
        sb.append("'").append(num).append("',");
        sb.append("'").append(num).append("',");
        sb.append("'").append(num).append("',");
        sb.append("'").append(num).append("',");
        sb.append("'").append(num).append("',");
        sb.append("'").append(num).append("',");
        sb.append("'").append(num).append("',");
        sb.append("'").append(num).append("',");
        //end here
        //start calculation of radar
        sb.append("'").append(radar).append("',");
        sb.append("'").append(radar).append("',");
        sb.append("'").append(radar).append("',");
        sb.append("'").append(radar).append("',");
        sb.append("'").append(radar).append("',");
        //ends here
        //mms incoming
        sb.append("'").append(radar).append("',");
        sb.append("'").append(radar).append("',");
        //ends here
        //voice incoming outgoing
        sb.append("'").append(radar).append("',");
        sb.append("'").append(radar).append("',");
        //end here
        //sms incoming outgoing
        sb.append("'").append(radar).append("',");
        sb.append("'").append(radar).append("',");
        //ends here
        //gprs calculation 
        sb.append("'").append(radar).append("',");
        sb.append("'").append(radar).append("',");
        sb.append("'").append(radar).append("',");
        sb.append("'").append(radar).append("')");
        //ends here
        System.out.println(sb.toString());
        String cql = sb.toString();
        session.execute(cql);
    }

这是表结构

CREATE TABLE CALL_RATIO_ANALYSYS(
A_NO TEXT,
JAN  TEXT,
FEB  TEXT,
MAR  TEXT,
APR  TEXT,
MAY  TEXT,
JUNE TEXT,
JULY TEXT,
AUG  TEXT,
SEP  TEXT,
OCT  TEXT,
NOV  TEXT,
DEC  TEXT,
RADAR_VOICE TEXT,
RADAR_SMS TEXT,
RADAR_MMS TEXT,
RADAR_GPRS TEXT,
RADAR_OTHER TEXT,
MMS_INCOMING TEXT,
MMS_OUTGOING TEXT,
VOICE_INCOMING TEXT,
VOICE_OUTGOING TEXT,
SMS_INCOMING TEXT,
SMS_OUTGOING TEXT,
GPRS_SOCIAL TEXT,
GPRS_MAIL TEXT,
GPRS_GOOGLE TEXT,
GPRS_ENTERTAINING TEXT,
GPRS_BUSINESS TEXT,
PRIMARY KEY(A_NO)
);

我无法理解列与数据不匹配的地方请帮忙

Answer 1

我建议你使用准备好的陈述。它不是您问题的直接解决方案，但您不应该像这样构建CQL语句。这是低效的，代码变得一团糟。可能有一个逗号或其他缺失的东西，但是尝试检查代码的语法比使用预准备语句重写它需要更多的时间：

PreparedStatement statement = session.prepare("INSERT INTO CALL_RATIO_ANALYSYS (A_NO,JAN,FEB,MAR,APR,MAY,JUNE,JULY,AUG,SEP,OCT,NOV,DEC,RADAR_VOICE,RADAR_SMS,RADAR_MMS,RADAR_GPRS,RADAR_OTHER,MMS_INCOMING,MMS_OUTGOING,VOICE_INCOING,VOICE_OUTGOING,SMS_INCOMING,SMS_OUTGOING,GPRS_SOCIAL,GPRS_MAIL,GPRS_GOOGLE,GPRS_ENTERTAINMENT,GPRS_BUSINESS) VALUES (?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?)");
BoundStatement boundStatement = statement.bind(detailsVO.getA_no(), num, num, num, num, num, num, num, num, num, num, num, num, radar, radar, radar, radar, radar, radar, radar, radar, radar, radar, radar, radar, radar, radar, radar);
session.execute(boundStatement);

保留准备好的陈述并重新使用它。

编辑所以这里真正的问题是你错过了最后一个参数的值。如果错误消息显示您的值数量错误，则计算值时会有所帮助。

如何解决cassandra中不匹配的列名/值？

1 个答案: