Question

我如何从互联网上读取音频流（例如http://70.36.96.24:13384/;stream.mp3）并使用Scala语言将其内容保存到我的本地磁盘？

我试过这样做：

val stream = new URL("http://70.36.96.24:13384/stream.mp3").openStream()

但它提出了这个例外：

java.io.IOException: Invalid Http response
at sun.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLConnection.java:1342)
at java.net.URL.openStream(URL.java:1037)
at .<init>(<console>:15)
at .<clinit>(<console>)
at .<init>(<console>:7)
at .<clinit>(<console>)
at $print(<console>)
    ...

相同的命令适用于其他流式网址：例如

http://174-123-32-173.webnow.net.br/98fm.mp3

更新：此代码适用于Linux，但不适用于Mac。有人知道原因吗？

UPDATE2：实际上这段代码适用于Java 6，但不适用于Java7。操作系统无关紧要。

Answer 1

您的代码无效，因为服务器未发送有效的HTTP响应。注意发送 HTTP请求，等待响应... 200没有标题，假设HTTP / 0.9

$ wget -O- "http://70.36.96.24:13384/;stream.mp3" 
--2014-01-20 17:09:12--  http://70.36.96.24:13384/;stream.mp3
Connecting to 70.36.96.24:13384... connected.
HTTP request sent, awaiting response... 200 No headers, assuming HTTP/0.9
Length: unspecified
Saving to: `STDOUT'

    [<=>                                                                                                                 ] 0           --.-K/s              ICY 200 OK
icy-notice1:<BR>This stream requires <a href="http://www.winamp.com/">Winamp</a><BR>
icy-notice2:SHOUTcast Distributed Network Audio Server/Linux v1.9.8<BR>
icy-name:Radio Brasileirissima
icy-genre:Musica Brasileira
icy-url:http://radiobrasileirissima.com.br
content-type:audio/mpeg
icy-pub:0
icy-br:64

....BINARY CONTENT SKIPPED....

您仍然可以通过跳过前几行直到字符序列\r\n\r\n，其中icy-br:64结束，并开始实际的AUDIO内容来读取数据。为此你可以创建一个Socket，连接到它并发送一个GET请求到`/ ;stream.mp3'并读取数据：

val timeout = 2000
val host = "70.36.96.24"
val port = 13384
val socket = new Socket
val endPoint = new InetSocketAddress(host, port)
socket.connect(endPoint, timeout);
// Here you send the GET request and read back the response.
// Every time you read the response, you have to skip
// the first few bytes until `\r\n\r\n`

<强> EDIT1

注意：您的GET请求必须包含额外的换行符才能成为HTTP请求

GET /;stream.mp3 HTTP/1.1

以下是同一网址上的工作示例：

  def socketurl = {
    val timeout = 2000
    val host = "70.36.96.24"
    val port = 13384
    val socket = new Socket
    val endPoint = new InetSocketAddress(host, port)
    socket.connect(endPoint, timeout);
    val (in, out) = (socket.getInputStream(), socket.getOutputStream())
    val httpRequest = "GET /;stream.mp3 HTTP/1.1\r\n\r\n"
    val command = httpRequest.getBytes()
    println(httpRequest)
    out.write(command)

    var buf = Vector(0, 0, 0, 0)
    var c = in.read()
    var cont = true
    while (c != -1 && cont) {
      buf = buf.drop(1) :+ c
      print(c.toChar)
      if (buf(0) == '\r' && buf(1) == '\n' && buf(2) == '\r' && buf(3) == '\n') {
        cont = false
        println("Its a match")
      }
      c = in.read()
    }

    while (c != -1) {
      // keep buffering the data from here on!
    }
  }

// call the method 
socketurl

如何在scala中读取网络流？

1 个答案: