Question

我有一个SELECT语句如下：

select car.car_ID,isnull(#tmpCount.RowCounter,0) AS RowCounter,ISNULL(#tmpNotServiced.DistinctCounter,0) AS DistinctCounter, ISNULL(#tmpNA.NACounter,0) AS NACounter, (isnull(#tmpCount.RowCounter,0) + ISNULL(#tmpNotServiced.DistinctCounter,0) + ISNULL(#tmpNA.NACounter,0)) AS Total, (CASE ISNULL(#tmpNotServiced.DistinctCounter,0) WHEN 0 THEN 'Closed' ELSE 'Open' END) AS Status
from car
left outer join #tmpCount
on car.AUD_ID = #tmpCount.car_ID
left outer join #tmpNotServiced
on car.AUD_ID = #tmpNotServiced.car_ID
LEFT OUTER JOIN #tmpNA
ON car.car_ID = #tmpNA.car_ID

然后存储的proc [p_GetServiced]计算全部打开并全部关闭。

CREATE PROCEDURE [dbo].[p_GetServiced] 

   AS
    BEGIN

SET NOCOUNT ON;

CREATE TABLE #tmp1 
(
    car_ID BIGINT,
    RowCounter BIGINT,
    DistinctCounter BIGINT,
    NACounter BIGINT,
    Total BIGINT,
    [Status] VARCHAR(MAX)
)
CREATE TABLE #tmp2 (car_ServiceDate DATETIME)

INSERT INTO #tmp1
EXEC [p_GetServiceDetail]

 SELECT [Status] AS [Serviced], COUNT(*) AS [Status] FROM #tmp1
 GROUP BY [Status]


INSERT INTO #tmp2
SELECT car_TargetDate FROM dbo.car
END
GO

我想让它返回'Serviced'和一小部分（2 of of 5），例如：Serviced（2 of 5）或NotServiced（3/5）

注意：2是开放的，5是总行

Answer 1

INSERT INTO #tmp1
EXEC [p_GetServiceDetail]

DECLARE @TotalRows BIGINT
SELECT @TotalRows = COUNT(*) FROM #tmp1

SELECT [Status] AS [Serviced], COUNT(*) AS [Status], @TotalRows AS [Rows]
FROM #tmp1
GROUP BY [Status]

或者，重新阅读您的问题，我认为更令人满意的方法是使用OVER条款：

SELECT DISTINCT
Status 
+ ' (' 
+ CONVERT(VARCHAR, count(*) OVER (PARTITION BY status)) 
+ ' OF ' 
+ CONVERT(VARCHAR, count(*) OVER ()) 
+ ')' 
FROM #tmp1

这产生以下结果：

Serviced (1 OF 4)
NotServiced (3 OF 4)

Answer 2

以下内容应该为您提供两行，包含两列，一列用于关闭，一列用于打开状态，输出格式为您想要的格式。

SELECT '[OPEN]', 
CONVERT(NVARCHAR(100), (SELECT COUNT(*) FROM #tmp1 WHERE [Status] = 'OPEN')) + 
' of ' + CONVERT(NVARCHAR(100), COUNT(*)) 
FROM   #tmp1
UNION
SELECT '[CLOSED]', 
CONVERT(NVARCHAR(100), (SELECT COUNT(*) FROM #tmp1 WHERE [Status] = 'CLOSED')) + 
' of ' + CONVERT(NVARCHAR(100), COUNT(*)) 
FROM  #tmp1

sql：在SELECT（存储过程）中写一个分数

2 个答案: