Question

我正在实现pretty simple API，并制作了一个简单的jQuery应用程序，用于构建本地URL，例如：

http://www.example.com?utm_campaign=test&utm_content=status&utm_source=facebook_saxocom&

当我调用API时，我使用这样的URL（更改了API密钥）：

http://api.shortswitch.com/shorten?apiKey=MYAPIKEY&format=json&callback=?http%3A%2F%2Fwww.example.com%3Futm_campaign%3Dtest%26utm_content%3Dstatus%26utm_source%3Dfacebook_saxocom%26&longUrl=http%3A%2F%2Fapi.shortswitch.com%2Fshorten%3FapiKey%3D402aaa42317ba1e3b70214740dbec7a5d33a7522%26format%3Djson%26callback%3D%3Fhttp%253A%252F%252Fwww.example.com%253Futm_campaign%253Dtest%2526utm_content%253Dstatus%2526utm_source%253Dfacebook_saxocom%2526

当我在浏览器中打开它时，我得到了我想要的有效JSON（有和没有URl编码）：

{
    "results": {
        "http://api.shortswitch.com/shorten?apiKey=MYAPIKEY&format=json&callback=?http%3A%2F%2Fwww.example.com%3Futm_campaign%3Dtest%26utm_content%3Dstatus%26utm_source%3Dfacebook_saxocom%26": {
            "shortUrl": "http://s.domain.com/3M",
            "hash": "3M",
            "longUrl": "http://api.shortswitch.com/shorten?apiKey=MYAPIKEY&format=json&callback=?http%3A%2F%2Fwww.example.com%3Futm_campaign%3Dtest%26utm_content%3Dstatus%26utm_source%3Dfacebook_saxocom%26"
        }
    },
    "errorCode": "0",
    "errorMessage": "",
    "statusCode": "OK"
}

我的通话功能：

function createNewShortUrl(url) {
        $.getJSON(url, { longUrl: url }, function (data) {
            if (data.statusCode == "OK") {
                for (var i in data.results) {
                    $('#shortenUrl').val(data.results[i].shortUrl);
                    break;
                }
                return;
            }
            alert(results.errorMessage);
        });
    }

我从不进去：

$.getJSON(url, { longUrl: url }, function (data) {

As：在函数内部没有调用alert（）函数，在Firebug调试器中我从未在其中找到断点。

所以我的问题是：我的getJSON函数出了什么问题？我应该更改什么才能获得""shortUrl": "http://s.domain.com/3M"元素？

编辑 - 我的回复

在使用以下确切数据进行调用时，我得到200响应：

?http: //www.dr.dk?utm_campaign=fdfd&utm_content=status&utm_source=facebook_saxocom&({
    "results": {
        "http://api.shortswitch.com/shorten?apiKey=MYAPIKEY&format=json&callback=?http%3A%2F%2Fwww.dr.dk%3Futm_campaign%3Dfdfd%26utm_content%3Dstatus%26utm_source%3Dfacebook_saxocom%26": {
            "shortUrl": "http://s.domain.com/3N",
            "hash": "3N",
            "longUrl": "http://api.shortswitch.com/shorten?apiKey=MYAPIKEY&format=json&callback=?http%3A%2F%2Fwww.dr.dk%3Futm_campaign%3Dfdfd%26utm_content%3Dstatus%26utm_source%3Dfacebook_saxocom%26"
        }
    },
    "errorCode": "0",
    "errorMessage": "",
    "statusCode": "OK"
});

当使用getJSON时，我从未进入函数调用

0 个答案: