Question

我有一些代码的一部分是这样的：

def topLevel():
    bugsendwindows = Toplevel(background="grey")
    bugsendwindows.title("report bug")
    buglabel1 = Label(bugsendwindows, text='title', background="white")
    buglabel1.place(x=10, y=20)
    bugtitleentry = Entry(bugsendwindows)
    bugtitleentry.place(x=50, y=20)
    bugtitleentry.focus_set()
    buglabel2 = Label(bugsendwindows, text="email", background="white")
    buglabel2.place(x=10, y=60)
    bugemailentry = Entry(bugsendwindows)
    bugemailentry.place(x=60, y=60)
    bugemailentry.focus_set()
    buglabel3 = Label(bugsendwindows, text="data", background="white")
    buglabel3.place(x=10, y=100)
    bugdataentry = Entry(bugsendwindows)
    bugdataentry.place(x=60, y=100, height=60)
    bugdataentry.focus_set()
    def Enter():
        global bugtitleentry
        global bugemail
        global bugdata
        bugtitle = bugtitleentry
        bugemail = bugemailentry
        bugdata = bugdataentry
        localtime = time.asctime(time.localtime(time.time()))
        bugwrite = open("bugreport", "w")
        bugwrite.write("title:")
        bugwrite.write(bugtitle, "\n")
        bugwrite.write("writer email:")
        bugwrite.write(bugemail, "\n")
        bugwrite.write("data:")
        bugwrite.write(bugdata, "\n")
        bugwrite.close()

    bugsend = Button(bugsendwindows, text="send",
        command=Enter)
    bugsend.place(x=10, y=150)

但是，每次点击发送时，都会说出这样的话：

bugtitle = bugtitleentry
NameError: global name 'bugtitleentry' is not defined

如何修复它以便Enter可以从topLevel将数据写入文件？

Answer 1

由于Enter嵌套在topLevel内，它将从闭包中获取这些名称，并且不需要global语句。

# ... <snip>
def Enter():
    bugtitle = bugtitleentry
    bugemail = bugemailentry
# </snip> ...

但是，作为旁注，我不确定数据写入是否会按预期工作。您可能需要在.get()对象上使用Entry方法。 e.g：

bugwrite.write(bugtitle.get() + "\n")  # and file.write only takes 1 argument!

从Entry获取数据

1 个答案: