Question

我有这门课（评估）

class schoolem_evaluation(osv.Model):
_name = 'schoolem.evaluation'
_columns = {
    'name' : fields.char('Evaluation',help="Champ automatique = periodeN_ExamenN_CoursX_SalleDeClasseS"),
    'aca_id' : fields.many2one('schoolem.aca','Annee Academique',required=True),
    'periode_id' : fields.many2one('schoolem.periode','Periode',required=True,help="Par exemple : trimestre01"),
    'examen_id' : fields.many2one('schoolem.examen','Examen',required=True),
    'salle_de_classe_id' : fields.many2one('schoolem.salle_de_classe','Salle de Classe',required=True),
    'cours_id' : fields.many2one('schoolem.cours','Cours',required=True),
    'note_ids' : fields.one2many('schoolem.note_evaluation','evaluation_id','Notes'),
}

和这个类（note_evaluation）

class schoolem_note_evaluation(osv.Model):
    _name = 'schoolem.note_evaluation'
    _order = 'etudiant_id'
    _columns = {
        'name' : fields.float('Note',digits=(6,2),required=True),
        'evaluation_id' : fields.many2one('schoolem.evaluation','Evaluation',),
        'etudiant_id' : fields.many2one('schoolem.etudiant','Etudiant',required=True),
        'rang' : fields.integer('Rang'),
        'observation' : fields.text('Observation'),
    }

我希望用户在选择Evaluation_form中最后一个字段（cours_id）的值时，能够通过on_change方法生成one2many note_evaluation行;并使生成的行直接出现在视图中，以便他可以插入每个note_evaluation行的名称值（注释）。并保存所有。

有可能吗？这是我当前的XML视图文件

<field name="cours_id"  context="{'evaluation_id': active_id, 'test': 1}" on_change="on_change_cours_id(examen_id,salle_de_classe_id,cours_id,aca_id)"/>
                    </group>
                    <notebook>
                        <page string="Inserer des notes">
                            <field nolabel="1" name="note_ids" context="{'evaluation_id': active_id}"/>
                        </page>

这是onchange函数：

def on_change_cours_id(self,cr, uid, ids,examen_id,salle_de_classe_id,cours_id,aca_id,context=None):

        context=context or {}

        #if context is None:

         #   context = {}
                for etud_id in etudiant_ids:

                    note_eval = self.pool.get('schoolem.note_evaluation')

                    if not context.get('id', False): #id de l'evaluation

                        context['id'] = context.get('evaluation_id')

                    eval_id = context.get('id', False)
                    raise osv.except_osv(('the form!'), (context.get('active_id')))

                    id = note_eval.create(cr, uid, {'name':0,'etudiant_id':etud_id,'evaluation_id':eval_id}, context=context)

使用它，on_change方法在数据库中创建note_evaluation，但用户界面不加载它们，one2many字段保持为空。我观察到数据库中的note_evaluation没有评估_id。

怎么办？

Answer 1

要使用onchange加载one2many数据，您不必从onchange函数创建one2many数据。您只需要为one2many字段创建值。例如

def on_change_cours_id(self,cr, uid, ids,examen_id,salle_de_classe_id,cours_id,aca_id,context=None):
    context=context or {}
    note_ids = []
    value = {}
    if ids:
        old_note_ids = self.pool.get('schoolem.note_evaluation').search(cr, uid,[('evaluation_id','in',ids)])
        self.pool.get('schoolem.note_evaluation').unlink(cr, uid, old_note_ids)
    etudiant_ids = []
    #search for etudiant_ids with the conditions examen_id,salle_de_classe_id,cours_id,aca_id etc
    for etud_id in etudiant_ids:
        note_ids.append((0,0,{'name':0,'etudiant_id':etud_id}))
    value.update(note_ids=note_ids)
    return {'value':value}

这里我做了一个取消链接，因为当你保存这条记录并再次以某种方式加载onchange时，将显示新的one2many列表。但是当保存时，你可以看到旧记录和新记录.SO unlink将删除旧记录。另外，当附加到note_ids时，我使用了0,0，{values}的元组，以下是对此的解释

(0, 0,  { values })    link to a new record that needs to be created with the given values dictionary
(1, ID, { values })    update the linked record with id = ID (write *values* on it)
(2, ID)                remove and delete the linked record with id = ID (calls unlink on ID, that will delete the object completely, and the link to it as well)
(3, ID)                cut the link to the linked record with id = ID (delete the relationship between the two objects but does not delete the target object itself)
(4, ID)                link to existing record with id = ID (adds a relationship)
(5)                    unlink all (like using (3,ID) for all linked records)
(6, 0, [IDs])          replace the list of linked IDs (like using (5) then (4,ID) for each ID in the list of IDs)

通过on_change方法创建和编辑one2many字段的项目

1 个答案: