Question

我想知道是否有任何方法可以存储java中的else条件？我的意思是有一个变量来表示条件。这是我的原始代码

private OnClickListener click2 = new OnClickListener() { 

            @Override
            public void onClick(View v) {
            tv1.setText("");
            List<Integer> mClickedButtonIds = new ArrayList<Integer>();

            int[] mDesiredOrder = new int[] { ans1.getId(), ans2.getId(), ans3.getId(),
                                              ans4.getId(), ans5.getId() }; 

            mClickedButtonIds.add(v.getId());
            if (mClickedButtonIds.size() >= mDesiredOrder.length )

            {            
                if (mClickedButtonIds.get(0) == mDesiredOrder[0] 
                    && mClickedButtonIds.get(1) == mDesiredOrder[1] 
                    && mClickedButtonIds.get(2) == mDesiredOrder[2]
                    && mClickedButtonIds.get(3) == mDesiredOrder[3]
                    && mClickedButtonIds.get(4) == mDesiredOrder[4]
                    )
                {
                    tv1.setText("Correct!");
                }
                else 
                {
                    tv1.setText("Try Again!");
                }
                mClickedButtonIds.clear();
             }
        }
 };

我打算把它改成像这样的东西

private OnClickListener click2 = new OnClickListener() { 

            @Override
            public void onClick(View v) {
            tv1.setText("");
            List<Integer> mClickedButtonIds = new ArrayList<Integer>();

            int[] mDesiredOrder = new int[] { ans1.getId(), ans2.getId(), ans3.getId(),
                                              ans4.getId(), ans5.getId(), ans6.getId() };   

            switch (main)
            {
            case 4 : Variable x = mClickedButtonIds.get(0) == mDesiredOrder[0] 
                    && mClickedButtonIds.get(1) == mDesiredOrder[1] 
                    && mClickedButtonIds.get(2) == mDesiredOrder[2]
                    && mClickedButtonIds.get(3) == mDesiredOrder[3];

            case 5 : Variable x = mClickedButtonIds.get(0) == mDesiredOrder[0] 
                    && mClickedButtonIds.get(1) == mDesiredOrder[1] 
                    && mClickedButtonIds.get(2) == mDesiredOrder[2]
                    && mClickedButtonIds.get(3) == mDesiredOrder[3]
                    && mClickedButtonIds.get(4) == mDesiredOrder[4];

            case 6: Variable x = mClickedButtonIds.get(0) == mDesiredOrder[0] 
                    && mClickedButtonIds.get(1) == mDesiredOrder[1] 
                    && mClickedButtonIds.get(2) == mDesiredOrder[2]
                    && mClickedButtonIds.get(3) == mDesiredOrder[3]
                    && mClickedButtonIds.get(4) == mDesiredOrder[4]
                    && mClickedButtonIds.get(5) == mDesiredOrder[5];
            }

            mClickedButtonIds.add(v.getId());
            if (mClickedButtonIds.size() >= mDesiredOrder.length )

            {            
                if (x)

                {
                    tv1.setText("Correct!");
                }
                else 
                {
                    tv1.setText("Try Again!");
                }
                mClickedButtonIds.clear();
             }
        }
 };

Variable x是我想问的问题。有没有任何方法可以这样做，或者有任何variable可以存储if else条件。导致原始代码，固定为5次点击。现在，我希望根据用户需要的点击次数来更改所需的点击次数。

Answer 1

根据代码段，考虑一个循环：

boolean result = true;
for (int i = 0; i < main; ++i) {
    result = result && mClickedButtonIds.get(i) == mDesiredOrder[i];
    if (!result)
        break; // short-circuit out from loop if false
}

// now you can use "result" to test whether the condition matched all "main" ids
if (result) {
    // correct
} else {
    // bzzt, try again
}

Answer 2

如果我理解正确，你希望x成为一个条件，你可以以编程方式改变（但符合某种结构），那么你可以使用接口Question和实现该接口的类来做到这一点

public interface Question {
    boolean getResponse(String condition1, int condition2);
}

public class StringIsLongCondition implements Question{

    public boolean getResponse(String condition1, int condition2) {
        return condition1.length()>condition2;
    }

}

public class StringIsShortCondition implements Question{

    public boolean getResponse(String condition1, int condition2) {
        return condition1.length()<condition2;
    }

}

然后使用

Question x;

//some code that selects the question
x= new StringIsShortCondition();

if(x.getResponse(someString, someInt){
     //do something
}

是否有任何方法在java中存储条件语句？

2 个答案: