Question

我们返回completedFilters.Select(GetFilterDetailDril)

我们在GetFilterDetailDril中有非常复杂的逻辑，它调用了很多函数。在没有调用函数的情况下在行中编写所有内容是不可能的。问题是我们想要稍后导出它，我们应该可以查询它。但是，如果我们调用函数，则c＃不能再使其可查询。有解决方案吗？

这就是我的回报

return filtersInDevelopment.Select(GetFilterDetailDrillDownModel)

这是函数

private FilterDevDetailDrillDownModel GetFilterDetailDrillDownModel(ALFilters alFilters)
    {
        alFilters = (alFilters.IsSample == 1 && alFilters.DestFilters.FirstOrDefault() != null) 
            ? alFilters.DestFilters.FirstOrDefault() : alFilters;
        var alFiltersDevelopment = alFilters.AlFiltersDevelopment.FirstOrDefault();

        if (alFiltersDevelopment != null)
        {
            var repository = new FilterRepository();
            var adt = alFiltersDevelopment.Adt ?? repository.GetAdt(alFilters);
            var edt = alFiltersDevelopment.Edt ?? repository.GetEdt(alFilters);

            var filterActiveMilestone = alFilters.FilterActiveMilestone;

            var milestoneTargetDate = (filterActiveMilestone != null)
                                          ? filterActiveMilestone.TargetDate
                                          : repository.GetFilterActiveMilestoneTargetDate(alFilters);

            var firstDevMilestone = alFilters.FilterMilestones.FirstOrDefault(
                x => x.MilestoneTypeId == FilterConst.START_DEVELOPMENT_MILESTONE);

            var startDevTime = (firstDevMilestone != null)
                                   ? firstDevMilestone.MilestoneDate
                                   : (DateTime?) null;

            string milestoneNmae = (filterActiveMilestone != null)
                                       ? filterActiveMilestone.dic_MilestoneTypes.NameForReport
                                       : string.Empty;

            double remainingMilestoneTime = (milestoneTargetDate.HasValue)
                                                ? milestoneTargetDate.Value.Subtract(DateTime.Now).Days
                                                : 0;

            double delayedTime = (edt != null && adt != null)
                                     ? adt.Value.Subtract(edt.Value).Days
                                     : 0 ;
            var site = db.dic_AL_Sites.Find(alFilters.SiteId);
            return new FilterDevDetailDrillDownModel
                {
                    FilterId = alFilters.ID,
                    Filter = alFilters.FilterCode,
                    StartDevDate = startDevTime,
                    MilelstoneName = milestoneNmae,
                    RemainingMilestoneTime = remainingMilestoneTime,
                    MilestoneEstimatedFinishDate = milestoneTargetDate,
                    EstimatedDevelopmentTime = alFiltersDevelopment.Edt,
                    DelayedTime = delayedTime,
                    Site = (site != null) ? site.Site_Name : string.Empty
                };
        }
        return null;
    }

很多逻辑...... 我想要i queriable return但这不是iqueriable这个filtersInDevelopment.Select（GetFilterDetailDrillDownModel）是可枚举的，没有可能看到查询：（

Answer 1

通过调用IEnumerable<T>扩展方法，可以将实现IQueryable<T>接口的类型转换为AsQueryable<T>：

http://msdn.microsoft.com/en-us/library/bb507003(v=vs.110).aspx

还有一个非通用的等价物：

http://msdn.microsoft.com/en-us/library/bb353734(v=vs.110).aspx

转换为IQueryable结果集

1 个答案: