Question

我遇到以下错误：

解析错误：语法错误，第7行的H：\ STUDENT \ S0213628 \ part2 \ friendslist.php中的意外T_CONSTANT_ENCAPSED_STRING

使用以下sql命令：

$sql = 
"SELECT ubuser.usr_firstname, ubuser.usr_lastname, ubuser.usr_DOB,  
ubuser2_1.usr_firstname & " " & ubuser2_1.usr_lastname AS UBFriend,
ubFriendsLink.ub_lnkID1, ubFriendsLink.ub_lnkID2, ubuser.usr_ID, ubuser2_1.usr_ID 
FROM ubuser AS ubuser2_1 INNER JOIN (ubFriendsLink INNER JOIN ubuser 
ON ubFriendsLink.ub_lnkID1 = ubuser.usr_ID) ON ubuser2_1.usr_ID = 
ubFriendsLink.ub_lnkID2 WHERE (((ubFriendsLink.ub_lnkID1) = ".$_SESSION['usr_ID'] .")) 
OR (((ubFriendsLink.ub_lnkID2) = ".$_SESSION['usr_ID'] ."))";

该命令旨在显示来自具有会话ID的用户以及通过friends链接表（使用ID1或ID2）链接到该用户的任何朋友的更新。

该命令似乎在访问中起作用，但是当我将sql合并到我的php页面时，该命令不起作用。

非常感谢任何帮助，谢谢。

Answer 1

在& "你关闭了你的起始报价。你需要用反斜杠来逃避它：

$sql = 
"SELECT ubuser.usr_firstname, ubuser.usr_lastname, ubuser.usr_DOB,  
ubuser2_1.usr_firstname & \" \" & ubuser2_1.usr_lastname AS UBFriend,
ubFriendsLink.ub_lnkID1, ubFriendsLink.ub_lnkID2, ubuser.usr_ID, ubuser2_1.usr_ID 
FROM ubuser AS ubuser2_1 INNER JOIN (ubFriendsLink INNER JOIN ubuser 
ON ubFriendsLink.ub_lnkID1 = ubuser.usr_ID) ON ubuser2_1.usr_ID = 
ubFriendsLink.ub_lnkID2 WHERE (((ubFriendsLink.ub_lnkID1) = ".$_SESSION['usr_ID'] .")) 
OR (((ubFriendsLink.ub_lnkID2) = ".$_SESSION['usr_ID'] ."))";

Answer 2

双引号内的双引号导致问题。

$sql = 
"SELECT ubuser.usr_firstname, ubuser.usr_lastname, ubuser.usr_DOB,  
ubuser2_1.usr_firstname & \" \" & ubuser2_1.usr_lastname AS UBFriend,
ubFriendsLink.ub_lnkID1, ubFriendsLink.ub_lnkID2, ubuser.usr_ID, ubuser2_1.usr_ID 
FROM ubuser AS ubuser2_1 INNER JOIN (ubFriendsLink INNER JOIN ubuser 
ON ubFriendsLink.ub_lnkID1 = ubuser.usr_ID) ON ubuser2_1.usr_ID = 
ubFriendsLink.ub_lnkID2 WHERE (((ubFriendsLink.ub_lnkID1) = ".$_SESSION['usr_ID'] .")) 
OR (((ubFriendsLink.ub_lnkID2) = ".$_SESSION['usr_ID'] ."))

意外的解析错误T_CONSTANT_ENCAPSED_STRING

2 个答案: