Question

我在Oracle SQL查询中遇到问题。我不知道如何得到这个查询的总和：

select call_type, channel
,count (case when status="no answer" then 1 end else 0) as cnt_no_answer
,count (case when status="answered" then 1 end else 0) as cnt_answer
from app_account.cc_call;

请帮帮我。谢谢！

Answer 1

再试一次，我编辑它：

SELECT call_type, channel,
       sum (CASE WHEN status='no answer' THEN 1 ELSE 0 END) AS cnt_no_answer,
       sum (CASE WHEN status='answered' THEN 1 ELSE 0 END) AS cnt_answer
FROM app_account.cc_call
GROUP BY call_type, channel;

Answer 2

获取已回答且未回答的记录总数而非计数。要获取已应答或未应答的所有记录的数量，请使用count（status）。要获取所有记录的计数，即状态为null的记录，请使用count（*）。字符串需要单引号，而不是双引号。案例陈述需要END。

EDITED（使用的END太多了）：

select call_type, channel
  , sum(case when status='no answer' then 1 else 0 end) as cnt_no_answer
  , sum(case when status='answered' then 1 else 0 end) as cnt_answer
  , count(status) as cnt_all_stated
  , count(*) as cnt_all_records
from app_account.cc_call
group by call_type, channel;

Answer 3

检查出来：

SELECT   CALL_TYPE,
       CHANNEL,
       COUNT (CASE WHEN UPPER(STATUS) = UPPER('no answer') THEN 1 ELSE NULL END)
           AS CNT_NO_ANSWER,
       COUNT (CASE WHEN UPPER(STATUS) = UPPER('answered') THEN 1 ELSE NULL END)
           AS CNT_ANSWER
FROM   APP_ACCOUNT.CC_CALL
GROUP BY   CALL_TYPE, CHANNEL;

Answer 4

选择call_type，channel

，总和（情况='无答案'然后1其他0结束时的情况）为cnt_no_answer

，总和（情况='回答'然后1，否则0结束时的情况）为cnt_answer

，将（状态）计为cnt_all_stated

，将（*）计为cnt_all_records

来自app_account.cc_call

按call_type分组，频道;

为什么usind结束两次

Answer 5

SELECT Call_type, Channel
,COUNT(CASE WHEN status="no answer" then 1 else 0 end ) as Cnt_no_answer
,COUNT(CASE WHEN status="answered" then 1 else 0 end ) as Cnt_answer
from App_account.cc_call 
GROUP BY call_type,channel;

我认为表减速有一些错误。请求给表结构。你想要SUM和你在那里计算我不认为这是错误但缺乏概述。请提供更多详情。

怎么得到这笔钱？

5 个答案: