基本上我正在尝试做一个与套接字通信的服务器 - 客户端程序。 我发现奇怪的是,服务器一旦启动它甚至不打印第一行。为什么是这样? 必须有一些东西从我身上溜走,我真的需要知道什么。
Server.c
int rvsock;
void stop(int sig){
close(rvsock);
}
void* worker(void* p){
struct mymsg m;
int err;
int sock = (int)p;
err = recv(sock,&m,sizeof(m),0);
if(err < 0){
printf("Failed to receive");
exit(1);
}
m.a = ntohl(m.a);
m.b = ntohl(m.b);
m.c = ntohl(m.c);
m.ip = ntohl(m.ip);
printf("Received numbers: %d %d %d from IP:%d", m.a,m.b,m.c,m.ip);
if(m.a < m.b && m.b <= m.c)
m.a = m.c;
else if(m.a < m.b && m.b >= m.c)
m.a = m.b;
else if(m.a > m.b && m.b <= m.c)
m.a = m.a;
m.a = htonl(m.a);
m.b = htonl(m.b);
m.c = htonl(m.c);
err = send(sock, &m,sizeof(m),0);
if(err < 0){
printf("Failed to send!");
close(sock);
return NULL;
}
close(sock);
return NULL;
}
int main(int argc, char** argv) {
printf("DAFUQ"); //It doesn't even print this. Why?
int port;
int sock;
int err;
unsigned int len;
struct sockaddr_in saddr;
struct sockaddr_in caddr;
pthread_t w[100];
int wn = 0;
int i;
sscanf(argv[1], "%d", &port);
signal(SIGINT, stop);
rvsock = socket(AF_INET, SOCK_STREAM, 0);
if(rvsock < 0) {
perror("Failed to create socket");
exit(1);
}
memset(&saddr, 0, sizeof(saddr));
saddr.sin_family = AF_INET;
saddr.sin_addr.s_addr = INADDR_ANY;
saddr.sin_port = htons(port);
err = bind(rvsock, (struct sockaddr*)&saddr,
sizeof(struct sockaddr_in));
if(err < 0) {
perror("Failed to bind");
exit(1);
}
err = listen(rvsock, 5);
if(err < 0) {
perror("Failed to listen");
close(rvsock);
exit(1);
}
while(1) {
len = sizeof(struct sockaddr_in);
sock = accept(rvsock, (struct sockaddr*)&caddr, &len);
if(sock < 0) {
perror("Failed to accept");
break;
}
pthread_create(&w[wn], 0, worker, (int*)sock);
wn++;
}
for(i=0; i<wn; i++) {
pthread_join(w[i], 0);
}
return 0;
}
client.c
int main(int argc, char** argv){
int sock;
int err;
int port;
struct sockaddr_in saddr;
struct mymsg m;
sscanf(argv[1], "%d", &port);
sock = socket(AF_INET, SOCK_STREAM, 0);
if(sock < 0){
printf("failed to create");
exit(1);
}
memset(&saddr, 0, sizeof(saddr));
saddr.sin_family = AF_INET;
saddr.sin_addr.s_addr = inet_addr("127.0.0.1");
saddr.sin_port = htons(port);
err = connect(sock, (struct sockaddr*)&saddr, sizeof(struct sockaddr_in));
if(err < 0){
perror("Failed to connect!");
exit(1);
}
printf("give a:");scanf("%d",&m.a);
printf("give b:");scanf("%d",&m.b);
printf("give c:");scanf("%d",&m.c);
m.a = htonl(m.a);
m.b = htonl(m.b);
m.c = htonl(m.c);
send(sock,&m,sizeof(m),0);
return 0;
}
message.h
struct mymsg{
int a;
int b;
int c;
int ip;
};
答案 0 :(得分:2)
在您的服务器中,您拥有此行。 printf打印到stdout FILE,当你启动程序时它会为你打开。
printf("DAFUQ"); //It doesn't even print this. Why?
man stdout
提供了有关stdout
的以下信息:
The stream stdout is line-buffered
when it points to a terminal. Partial lines will not appear until
fflush(3) or exit(3) is called, or a newline is printed.
您不打印换行符,不刷新stdout
并且您的程序没有退出,因此无法满足将输出打印到终端所需的任何条件。
因此,为了打印该行,您有3个选项:
1
printf("DAFUQ"); //It doesn't even print this. Why?
fflush(stdout);
2
printf("DAFUQ\n"); /*notice added '\n'*/
3
打印后调用exit()
(可能不是很有用)。