Question

"\:(.*)$"

大家好我正在使用上面的表达式删除:（冒号）之前的所有字符串，但它在此之前给了我所有的字符串。我怎样才能做到这一点。非常感谢。

我的字符串是：

This is text: Hi here we go

我得到：This is text

我想：Hi here we go

更新了代码

Sub Main()
    Dim input As String = "This is   text with   : far  too   much  "
    Dim pattern As String = "\:(.*)$"
    Dim replacement As String = " "
    Dim rgx As New Regex(pattern)
    Dim result As String = rgx.Replace(input, replacement)

    Console.WriteLine("Original String: {0}", input)
    ' MsgBox("Original String: {0}")
    Console.WriteLine("Replacement String: {0}", result)
    MsgBox("Original String: {0}")
End Sub

Answer 1

尝试这种模式。这将帮助您匹配冒号后的字符串

/ ：（）/

或

/ :(。+）/

Answer 2

应该是：

Dim pattern As String = "(.*)\:"
' in vb if above one doesn't work, then try this one
' Dim pattern As String = "^(.*)\:"
' also i don't think we need to use any brackets here as well.

这个正则表达式意味着冒号（:)之前的任何内容，你在示例中使用冒号（:)之后的任何内容。

Answer 3

如果你没有在RegEx上设置死机，那么你也可以使用

 Dim result As String
 result = Strings.Split(Input, ":", 2)(1)

这会将输入拆分为包含两个元素的数组。第一个元素是第一个“：”之前的文本，第二个元素是之后的文本。

删除之前的所有字符串：

更新了代码

3 个答案: