Question

你好请帮我把字符串转换成日期： - 谷歌搜索了这个，但没有得到理想的结果

    <?php

$todaydate= $_GET['date']; //sending 201213 ie index.php?date=201213

$todaydate=preg_replace("/[^0-9,.]/", "", $todaydate);

echo $todaydate."----------"; //prints 201213

$todaydate = date("ymd", strtotime($todaydate));

echo $todaydate."----------"; // i want to print 131220 here but it prints today's date
?>

Answer 1

尝试使用mktime：

<?php
    $todaydate  = $_GET['date']; //sending 201213 ie index.php?date=201213
    $todaydate  = preg_replace("/[^0-9,.]/", "", $todaydate);
    echo $todaydate."----------"; //prints 201213

    $d = substr($todaydate, 0, 2);
    $m = substr($todaydate, 2, 2);
    $y = substr($todaydate, 4, 2);
    $t = mktime (0, 0, 0, $m, $d, $y);

    $todaydate = date("ymd", $t);
    echo $todaydate."----------"; // i want to print 131220 here but it prints today's date
?>

Answer 2

更简单的解决方案：

<?php
        $todaydate  = $_GET['date']; //sending 201213 ie index.php?date=201213
        $todaydate  = preg_replace("/[^0-9,.]/", "", $todaydate);   
        $date = DateTime::createFromFormat('dmy', $todaydate);
        echo $date->format('ymd');
?>

使用此代码，您可以使用任何格式显示日期，因为您现在拥有有效日期。

在“ymd”中将字符串转换为php中的日期

2 个答案: