你好,我在理解编译器为这段代码抱怨的内容时遇到了一些问题。
template<typename T> struct sEventColl {
T __d__;
list<string> event_list;
sEventColl(T d, const string& eventStr) :
__d__(d) {
event_list.push_back(eventStr);
}
template<typename U>
sEventColl(const sEventColl<U>& other) {
__d__ = other.__d__;
this->event_list.clear();
for (typename list<string>::const_iterator it =
other.event_list.crbegin(); it != other.event_list.crend();
it++) {
event_list.push_back(*it);
}
}
~sEventColl(){}
bool operator<=(const T & d) const {
return ((d == __d__) || (__d__ < d));
}
bool operator>=(const T & d) const {
return ((__d__ == d) || (__d__ > (d)));
}
bool removeEvent(string eventText) {
for (typename list<string>::iterator it = event_list.begin();
it != event_list.end(); it++) {
if (*it == eventText) {
event_list.erase(it);
return true;
}
}
return false;
}
bool addEvent(const string event) {
/* Check if object already exist */
for (typename list<string>::const_iterator it = event_list.begin();
it != event_list.end(); it++) {
if (event == *it)
return false;
}
event_list.push_back(event);
return true;
}
bool isEmpty() {
return event_list.empty();
}
friend ostream& operator<<(ostream & os, const sEventColl & ecoll) {
for (typename list<string>::const_iterator it = ecoll.cbegin();
it != event_list.cend(); it++) {
os << __d__ << " : " << *it << endl;
}
return os;
}
};
编译器输出:
calendar.h:在函数'std :: ostream&amp; lab2 :: operator&lt;&lt;(std :: ostream&amp;,const lab2 :: sEventColl&amp;)': calendar.h:49:16:错误:无效使用非静态数据成员'lab2 :: sEventColl :: event_list' calendar.h:110:11:错误:从这个位置 calendar.h:48:4:错误:无效使用非静态数据成员'lab2 :: sEventColl :: d ' calendar.h:111:10:错误:从这个位置
答案 0 :(得分:0)
解决了它..
在
中friend ostream& operator<<(ostream & os, const sEventColl & ecoll) {
for (typename list<string>::const_iterator it = ecoll.cbegin();
it != event_list.cend(); it++) {
os << __d__ << " : " << *it << endl;
}
return os;
}
我应该通过ecoll参考访问成员!