我正在构建一个单页应用程序，用于查找基于流派的电影。目前它在主窗体和注释表单上使用POST方法。
通知表单目前使用GET方法获取电影ID（选择此选项是为了避免刷新重置电影建议过程的页面）。
目前，如果我在主表单上点击提交，则网址会更改为 index.php？，并且电影会根据条件成功加载。
我的问题是：为什么我的filmID不会以主要形式回响？如何在不使用GET方法的情况下将电影ID粘贴到当前URL中？因此，例如，如果我输入 index.php？filmID = 6 ，它会加载有关“黑暗骑士”的信息。
index.php（按要求修剪）
//If submit comment pressed, get data and input
if(trim($_POST['submit']) == "Submit comment"){
$userID = $_SESSION['userID'];
$likeit = $_POST['yesornoList'];
$filmID = $_GET['filmID'];
$comment = clean_string($db_server, $_POST['commentBox']);
if ($comment != '') {
$query = "INSERT INTO comments (userID, filmID, comment, likeit)
VALUES ('$userID', '$filmID', '$comment', '$likeit')";
mysqli_select_db($db_server, $db_database);
mysqli_query($db_server, $query) or
die("Insert failed: " . mysqli_error($db_server)) . $query;
echo $commentMessage = "<section>Thanks for your comment!</section>";
}
}else{
if (isset($_POST['genreList']) && ($_POST['genreList'] != "")){
$genre = clean_string($db_server, $_POST['genreList']);
//create the SQL query
$query = "SELECT * FROM films WHERE genreID=$genre ";
//$endquery = " AND (";
$endquery = "";
$orFlag = false;
if (isset($_POST['streamingCheckbox1']) && ($_POST['streamingCheckbox1'] != '')){
$endquery .= " netflix IS NOT NULL";
$orFlag = true;
}
if (isset($_POST['streamingCheckbox2']) && ($_POST['streamingCheckbox2'] != '')){
if($orFlag){
$endquery .= " OR ";
}
$endquery .= " lovefilmInstant IS NOT NULL";
$orFlag = true;
}
if (isset($_POST['streamingCheckbox3']) && ($_POST['streamingCheckbox3'] != '')){
if($orFlag){
$endquery .= " OR ";
}
$endquery .= " blinkbox IS NOT NULL";
}
if($endquery != "") $query .= " AND (" . $endquery . ")";
$query .= " ORDER BY (SELECT FLOOR(MAX(filmID) * RAND()) FROM films) LIMIT 0,1;";
//query the database
mysqli_select_db($db_server, $db_database);
$result = mysqli_query($db_server, $query);
if (!$result) die("Database access failed: " . mysqli_error($db_server) . $query);
//if there are any rows, print out the contents
if ($row = mysqli_fetch_array($result)) {
//Whether to display links or not for purchase and streaming
$filmID = $row['filmID'];
//Body content for film
$str_result =
"<section> This is where the film details are
</section>"
. $commentMessage . "
<section>
<form id='frmFilmComments' action='index.php?filmID=" . $filmID . "#comments' method='post'>
<a id='comments' class='anchor'></a>
<h3>Comments</h3>
<p><span class='bold'>Did you like " . $row['filmName'] ."?</span></p>
<select class='selectbox' name='yesornoList'>
<option value='Yes'>Yes</option>
<option value='No'>No</option>
</select>
<p><span class='bold'>Provide your feedback here:</span></p>
<textarea id='commentBox' class='insertComment' rows='2' cols='30' name='commentBox'></textarea><br>
<input class='formButton' type='submit' id='submit' name='submit' value='Submit comment'/>
</form>
";
mysqli_free_result($result);
//Code to print comments goes here
}else{
$str_result = "<section><h3>Sorry</h3><p>We couldn't find any films that match your terms. </br> <a href='#findafilm'>Please try again.</a></p></section>";
}
}else{
//$str_result = "<section><h3>Sorry</h3><p>No genre was chosen.</br><a href='home.php'>Please try again.</a></p></section>";
}
$message = $str_result . $likedcomments . $dislikedcomments . "<section/>";
}
}
//Exisiting code to handle options list
?>
<div id="top" class="content container headerMargin">
<div class="content wrapper">
<form id="frmFilmFinder" action="index.php?filmID=<?php echo $filmID; ?>" method="post">
<section>
<h2>Welcome <?php echo $_SESSION['username'] ?>!</h2>
<p class="underHeader">You are now logged in and ready to use the Film Finder.</p>
</section>
<section>
<a class="anchor" id="findafilm"></a>
<h3>Find a film</h3>
<h4>Choose a genre:</h4>
<select class="selectbox" name="genreList">
<?php echo $str_options; ?>
</select>
<h4>Choose a streaming service:</h3>
<input type="checkbox" class="checkbox" id="streamingCheckbox1" name="streamingCheckbox1" value="Netflix"><span class="checkboxText">Netflix</span><br>
<input type="checkbox" class="checkbox" id="streamingCheckbox2" name="streamingCheckbox2" value="LoveFilm"><span class="checkboxText">LoveFilm Instant</span><br>
<input type="checkbox" class="checkbox" id="streamingCheckbox3" name="streamingCheckbox3" value="blinkbox"><span class="checkboxText">blinkbox</span><br>
<input type="submit" class="formButton filmSearch" id="submit" name="submit" value="Submit"/>
<p><span class="italic">Leave all unticked if you wish to buy the film</span></p>
</section>
</form>
<?php echo $message; ?>
</div>
</div>
答案 0 :(得分：1)
主要是，您需要确保在撰写表单时设置了$filmID。将它传递给查询字符串是有效的（即使您正在发布表单，也可通过$_GET['filmID']访问。它将起作用并达到其目的，但请务必评论您正在做什么以及为什么这样您还记得下一步时间。
您将其填充为$filmID = $_GET['filmID']，但仅限于评论表单的表单处理中。这意味着除非您收到评论，否则不会设置。您应该在逻辑中移动更高的位置，如果已设置，则始终。
// near the top, outside if() conditions:
$filmID = isset($_GET['filmID']) ? $_GET['filmID'] : null;
考虑在第一次设置它时将其存储到$_SESSION['filmID']以及任何时候更改，所以你可以在任何需要它的脚本上存储它。
最后，在评论主题中提到的一个附带问题，使用MySQLi是一个开始，开始熟悉准备语句如何通过mysqli::prepare()使用绑定参数。所有查询输入变量都应该通过绑定参数来处理，从而无需转义。这是一般的最佳实践。