我编写了一个代码,用于从联系人中获取联系人姓名,电话号码和图像,并将其显示在android中的列表视图中。它工作正常,但需要更多时间来加载。我曾尝试在代码的某些部分使用多线程。但加载时间并未减少。
以下是onCreate()
方法:
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
lvDetail = (ListView) findViewById(R.id.listView1);
fetchcontacts();
lvDetail.setAdapter(new MyBaseAdapter(context, myList));
}
以下是获取联系人的代码:
private void fetchcontacts() {
// TODO Auto-generated method stub
Cursor cursor = getContentResolver().query(ContactsContract.Contacts.CONTENT_URI, null,
null, null, ContactsContract.Contacts.DISPLAY_NAME + " ASC");
int count = cursor.getCount();
if (count > 0) {
Toast.makeText(context, "count >0", Toast.LENGTH_SHORT).show();
while (cursor.moveToNext()) {
String columnId = ContactsContract.Contacts._ID;
int cursorIndex = cursor.getColumnIndex(columnId);
String id = cursor.getString(cursorIndex);
name = cursor.getString(cursor
.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
Toast.makeText(context, "Toast 1", Toast.LENGTH_SHORT).show();
int numCount = Integer.parseInt(cursor.getString(cursor
.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER)));
if (numCount > 0) {
Toast.makeText(context, "Toast 2", Toast.LENGTH_SHORT).show();
Cursor phoneCursor = getContentResolver().query(
ContactsContract.CommonDataKinds.Phone.CONTENT_URI,null,
CommonDataKinds.Phone.CONTACT_ID+" = ?", new String[] { id
}, ContactsContract.Contacts.DISPLAY_NAME + " ASC");
while (phoneCursor.moveToNext()) {
Toast.makeText(context, "Toast 3", Toast.LENGTH_SHORT).show();
phoneNo = phoneCursor.getString(phoneCursor
.getColumnIndex(ContactsContract.CommonDataKinds.
Phone.NUMBER));
String image_uri = phoneCursor
.getString(phoneCursor
.getColumnIndex(ContactsContract.CommonDataKinds.Phone.PHOTO_URI));
if (image_uri != null) {
Toast.makeText(context, "Toast 4", Toast.LENGTH_SHORT).show();
System.out.println(Uri.parse(image_uri));
try {
bitmap = MediaStore.Images.Media
.getBitmap(this.getContentResolver(),
Uri.parse(image_uri));
// sb.append("\n Image in Bitmap:" + bitmap);
// System.out.println(bitmap);
} catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
Toast.makeText(context, name, Toast.LENGTH_SHORT).show();
getDataInList(name,phoneNo,bitmap);
name=null;
phoneNo=null;
Drawable myDrawable = getResources().getDrawable(R.drawable.star1);
bitmap = ((BitmapDrawable) myDrawable).getBitmap();
}
phoneCursor.close();
}
}
}
这里listview的setAdapter()函数在将所有联系人提取到ArrayList之后正在工作。有谁知道如何在获取联系人期间显示联系人?任何示例代码?
答案 0 :(得分:5)
1.仅从您需要的Cursor
中读取列,根据您的要求,您只需 _ID,HAS_PHONE_NUMBER,DISPLAY_NAME ,因此请更改光标读数
Cursor cursor = getContentResolver().query(
ContactsContract.Contacts.CONTENT_URI,
new String[] { ContactsContract.Contacts._ID,
ContactsContract.Contacts.HAS_PHONE_NUMBER,
ContactsContract.Contacts.DISPLAY_NAME }, null, null,
ContactsContract.Contacts.DISPLAY_NAME + " ASC");
2.不要在UI线程中完成整个过程。请使用AsyncTask
代替
注意:这两个步骤将在某种程度上解决。但不完全
答案 1 :(得分:0)
larse大小的联系人在backround任务中使用。 Uri uri = Uri.withAppendedPath(ContactsContract.PhoneLookup.CONTENT_FILTER_URI,Uri.encode(number [i]));
ContentResolver contentResolver = getContentResolver();
Cursor search = contentResolver.query(uri, new String[]{ContactsContract.PhoneLookup._ID,
ContactsContract.PhoneLookup.DISPLAY_NAME}, null, null, null);
try {
if (search != null && search.getCount() > 0) {
search.moveToNext();
name = search.getString(search.getColumnIndex(ContactsContract.Data.DISPLAY_NAME));
id = search.getString(search.getColumnIndex(ContactsContract.Data._ID));
System.out.println("name" + name + "id" + id);
/* tv_name.setText(name);
tv_id.setText(id);
tv_phone.setText(number);*/
}
} finally {
if (search != null) {
search.close();
}
}
答案 2 :(得分:0)
对我来说最快的方式。
ContentResolver cr = mContext.getContentResolver(); Cursor cursor= mContext.getContentResolver().query(ContactsContract.Contacts.CONTENT_URI, PROJECTION, "HAS_PHONE_NUMBER <> 0", null, null); if (cursor!= null) { final int displayNameIndex = cursor.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME); final int numberIndex = cursor.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER); final int idIndex= cursor.getColumnIndex(ContactsContract.Contacts._ID); String displayName, number = null, idValue; while (cursor.moveToNext()) {
displayName = cursor.getString(displayNameIndex);
idValue= cursor.getString(idIndex);
Cursor phones = mContext.getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, "contact_id = '" + idValue + "'", null, null);
phones.moveToFirst();
try {
number = phones.getString(phones.getColumnIndex("data1"));
}
catch (CursorIndexOutOfBoundsException e)
{`
}
phones.close();
userList.add(new ContactModel(displayName , number , null , }
答案 3 :(得分:0)
我通过减少重复查询来制作它,价格昂贵。我最好的解决方案是该方法找到每个联系人的所有移动电话和电子邮件,并插入列表中的每个联系人值。现在风暴很快:)。
//contact entity
public class MobileContact {
public String name;
public String contact;
public Type type;
public MobileContact(String contact, Type type) {
name = "";
this.contact = contact;
this.type = type;
}
public MobileContact(String name, String contact, Type type) {
this.name = name;
this.contact = contact;
this.type = type;
}
public enum Type {
EMAIL, PHONE
}
@Override
public String toString() {
return "MobileContact{" +
"name='" + name + '\'' +
", contact='" + contact + '\'' +
", type=" + type +
'}';
}
}
// method for collect contacts
public List<MobileContact> getAllContacts() {
log.debug("get all contacts");
List<MobileContact> mobileContacts = new ArrayList<>();
ContentResolver contentResolver = context.getContentResolver();
// add all mobiles contact
Cursor phonesCursor = contentResolver.query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, new String[]{ContactsContract.CommonDataKinds.Phone.NUMBER, ContactsContract.CommonDataKinds.Phone.CONTACT_ID}, null, null, null);
while (phonesCursor != null && phonesCursor.moveToNext()) {
String contactId = phonesCursor.getString(phonesCursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.CONTACT_ID));
String phoneNumber = phonesCursor.getString(phonesCursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER)).replace(" ", "");
mobileContacts.add(new MobileContact(contactId, phoneNumber, MobileContact.Type.PHONE));
}
if (phonesCursor != null) {
phonesCursor.close();
}
// add all email contact
Cursor emailCursor = contentResolver.query(ContactsContract.CommonDataKinds.Email.CONTENT_URI, new String[]{ContactsContract.CommonDataKinds.Email.DATA, ContactsContract.CommonDataKinds.Email.CONTACT_ID}, null, null, null);
while (emailCursor != null && emailCursor.moveToNext()) {
String contactId = emailCursor.getString(emailCursor.getColumnIndex(ContactsContract.CommonDataKinds.Email.CONTACT_ID));
String email = emailCursor.getString(emailCursor.getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA));
mobileContacts.add(new MobileContact(contactId, email, MobileContact.Type.EMAIL));
}
if (emailCursor != null) {
emailCursor.close();
}
// get contact name map
Map<String, String> contactMap = new HashMap<>();
Cursor contactsCursor = contentResolver.query(ContactsContract.Contacts.CONTENT_URI, new String[]{ContactsContract.Contacts._ID, ContactsContract.Contacts.DISPLAY_NAME, ContactsContract.Contacts.HAS_PHONE_NUMBER}, null, null, ContactsContract.Contacts.DISPLAY_NAME);
while (contactsCursor != null && contactsCursor.moveToNext()) {
String contactId = contactsCursor.getString(contactsCursor.getColumnIndex(ContactsContract.Contacts._ID));
String contactName = contactsCursor.getString(contactsCursor.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
contactMap.put(contactId, contactName);
}
if (phonesCursor != null) {
phonesCursor.close();
}
// replace contactId to display name
for (MobileContact mobileContact : mobileContacts) {
String displayName = contactMap.get(mobileContact.name);
mobileContact.name = displayName != null ? displayName : "";
}
// sort list by name
Collections.sort(mobileContacts, new Comparator<MobileContact>() {
@Override
public int compare(MobileContact c1, MobileContact c2) {
return c1.name.compareTo(c2.name);
}
});
return mobileContacts;
}