Question

我需要使用双重机制将facebook登录添加到我的网站。当用户单击fb登录时，第一个触发，脚本检查我的数据库中是否存在fbid，如果为true则设置会话。如果fbid不存在，脚本会选择其他数据，如用户名和电子邮件，然后将fbid插入到DB中。问题是如果fbid不存在，我的代码会在db中插入错误的id。这是我的代码：

 <?php
 require_once('lib/facebook.php');
  include "db.php";
$statara='';
  $config = array(
    'appId' => 'xxxxxxxx',
    'secret' => 'xxxxxxx',
  );

  $facebook = new Facebook($config);
  $user_id = $facebook->getUser();
$fb_user='';
    if($user_id) {

      // We have a user ID, so probably a logged in user.
      // If not, we'll get an exception, which we handle below.
      try {
        $fql = 'SELECT uid,name from user where uid = ' . $user_id;
        $ret_obj = $facebook->api(array(
                                   'method' => 'fql.query',
                                   'query' => $fql,
                                 ));

        // FQL queries return the results in an array, so we have
        //  to get the user's name from the first element in the array.

    }
       catch(FacebookApiException $e) {
        // If the user is logged out, you can have a 
        // user ID even though the access token is invalid.
        // In this case, we'll get an exception, so we'll
        // just ask the user to login again here.
        $login_url = $facebook->getLoginUrl(); 
        $udj= 'Please <a href="' . $login_url . '">login. redef</a>';
        error_log($e->getType());
        error_log($e->getMessage());
      }   
    } else {

      // No user, so print a link for the user to login
      $login_url = $facebook->getLoginUrl();
     $udj= '<a href="' . $login_url . '" id="fblogin">login. redeff</a>';

    }

 if ($user_id){
        $sqlf=mysql_query("SELECT * FROM users where fbid='$user_id'");
        $sqlf_num=mysql_num_rows($sqlf);
    if ($sqlf_num > 0) { //// Users fbid exist put out his username from db
while($frow=mysql_fetch_array($sqlf)){
$username=$frow['username'];

$fb_user=$username;

}}else{ //// users fbid does not exist so insert him 
    $fb_user="$user_id to addd";
    $sqli=mysql_query("INSERT INTO users(fbid) VALUES('$user_id')");
$stat= "<br><a href='logout.php'>logout ".$fb_user." </a><br>";
 }

} else{
 $stat="<br>not connected<br>";
 }
 echo "$udj $fb_user ";

?>

Answer 1

逻辑似乎可以使用FQL获取用户详细信息。现在我看到您将用户添加到数据库中的部分

$fb_user="$user_id to addd"; // not sure what is this
$sqli=mysql_query("INSERT INTO users(`fbid`) VALUES('".$user_id."')");
$stat= "<br><a href='logout.php'>logout ".$fb_user." </a><br>";

你能试试吗

$sqli=mysql_query("INSERT INTO users(`fbid`) VALUES('".$user_id."')");

此外，您可以在执行插入之前通过回显$ user_id进行调试。

此外，您可以使用图形api调用而不是FQL来获取用户信息

$facebook->api('/me');

Answer 2

尝试将表格中的fbid 列类型从 INT 更改为 BIGINT 。这对我有用。

其他信息，我的BIGINT列类型默认长度为20。

Facebook登录将错误的id插入mysql数据库

2 个答案: