Question

我正在创建一个在c ++中使用的彩票程序，我想知道这段代码可以用来比较数字

do
{
    for (int Num = 0; Num < 6; Num++) {
        if (RandomNumber[Num] == Numbers[Games][Num]) {
            cout << "A Number matches" << Numbers[Games][Num] << endl;
        } else {
            cout << "Bad Luck, Try Again Next Time" << Numbers[Games][Num] << endl;
        }
    }
    Games = Games - 1;
} while (Games > -1);

每当我尝试运行此代码时，它都无法正确地比较数字，我能想到的唯一问题是无法运行代码来执行我想要的操作。任何有关此问题的帮助将不胜感激。干杯

Answer 1

我认为你应该不仅在Numbers [游戏] [Num]上检查所有数字[游戏]，但我只能猜测。我不知道你的全部想法。我认为你应该做那样的事情：

do
{
    for (int Num=0; Num<6; Num++)
    {
        bool exist = false;
        for( int i = 0; i < 6; ++i ) 
        {
             if (RandomNumber[Num] == Numbers[Games][i]) exist = true;
        }
        if (exist)           
        {
            cout<<"A Number matches"<<RandomNumber[Num]<<endl;
        }
        else
        {
           cout<<"Bad Luck, Try Again Next Time"<<RandomNumber[Num]<<endl;
        }
    }
    Games = Games - 1;
}
while (Games>-1);
}

我没有测试这段代码。这不是最好的性能解决方案。

Answer 2

假设您正在尝试匹配整行，那么您当前的逻辑似乎并不是很好这是@Adam Folwarczny发布的略微修改版本。

#include <iostream>

int main (void)
{
    int Numbers [] [6] = 
    {
        {1, 2, 3, 4, 5, 6},
        {7, 8, 9, 10, 11, 12},
        {13, 14, 15, 16, 17, 18},
        {19, 20, 21, 22, 23, 24}
    };

    int RandomNumber [] = {13, 14, 15, 16, 17, 18} ;

    int nGames = sizeof (Numbers) / sizeof (Numbers [0]) ;
    int nNumbers = sizeof (RandomNumber) / sizeof (RandomNumber [0]) ;

    // This assumes order matters.
    for (int i = 0; i < nGames; ++i) {

        bool bWin = true ;

        for (int j = 0; j < nNumbers; ++j) {
            if (RandomNumber [j] != Numbers [i] [j]) {
                bWin = false ;
                break ;
            }
        }

        if (bWin == true) {
            std::cout << "Player " << (i + 1) << " won!" << std::endl ;
        }

        else {
            std::cout << "Player " << (i + 1) << " lost!" << std::endl ;
        }
    }

    return 0 ;
}

如何将1d数组中的值与c ++中的2d数组进行比较

2 个答案: