我正在尝试将数据从数据库中提取到选择框中,但是当数据被拉出时,它会进入一个“td”而不是单独的td。我正在努力实现如下所示的结果
但我一直得到这个结果
这是我的代码
<?php
$data_array = array();
$result2 = mysql_query("SELECT * FROM `firefightersonscene`
JOIN `firefighterinfo` ON `firefightersonscene`.`FireFighterInfo_fighterID` = `firefighterinfo`.`fighterID`
JOIN `stationlocation` ON `firefighterinfo`.`StationLocation_locationID`=`stationlocation`.`locationID`
WHERE `IncidenceOfFire_incidentID`='$getIncID' ORDER BY `firstName`");
if(mysql_num_rows($result2) > 0)
{
while($rows2 = mysql_fetch_object($result2))
{
$data_array[] = $rows2;
}
}
?>
<form action="core_viewfireoccurrence.php?incidentID=<?php echo $rows->incidentID; ?>" method="post" class="view_occurrence_form">
<table id="myTable">
<thead>
<tr>
</tr>
</thead>
<tbody>
<tr>
<td class="count">1</td>
<td>
<?php
foreach($data_array as $rows2):
$fighterID = $rows2->FireFighterInfo_fighterID;
$results = mysql_query("SELECT `fighterID`, `firstName`, `middleName`, `lastName`, `stationlocation`.`exactlocation`
FROM `firefighterinfo`
JOIN `stationlocation` ON `firefighterinfo`.`StationLocation_locationID`=`stationlocation`.`locationID` ORDER BY `firstName`");
echo '<select name="fireman[]" required><option value=""></option>';
while($row = mysql_fetch_array($results))
{
if($row['fighterID'] == $fighterID)
echo '<option selected>'. $row['firstName']." ".$row['middleName']." ".$row['lastName'].", ".$row['exactlocation'].'</option>';
else
echo '<option>'. $row['firstName']." ".$row['middleName']." ".$row['lastName'].", ".$row['exactlocation'].'</option>';
}// end while
echo '</select><br>';
endforeach;
?>
</td>
<td>
<input type="button" value="X" class="removeVar"/>
</td>
</tr>
</tbody>
<tfoot>
<tr>
<td>
<input type="button" id="addVar" value="Add Item"/>
</tr>
</tfoot>
</table>
</form>
JS CODE
<script type="text/javascript">
$('form').on('click', '.removeVar', function(){
$(this).closest('tr').remove();
$('.count').each(function(i){
$(this).text(i + 1);
});
});
//add a new node
$('#addVar').on('click', function(){
var varCount = $('#myTable tr').length - 1;
$node = ['<tr>',
'<td class="count">'+varCount+'</td>',
'<td><select name="fireman[]" class="ctlGroup" required>',
'<option value=""></option>',
'<?php require("php/fireman_list.php"); ?>',
'</select></td>',
'<td><input type="button" value="X" class="removeVar"/>',
'</td></tr>'].join('\n');
$('#myTable > tbody:last').append($node);
});
</script>
答案 0 :(得分:2)
您需要将整个表格行放在循环中。您还需要添加一个变量来为您计算行号。
<?php
$row =1;
foreach($data_array as $rows2):
?>
<tr>
<td class="count"><?php echo $row; ?></td>
<td>
<?php
$fighterID = $rows2->FireFighterInfo_fighterID;
$results = mysql_query("SELECT `fighterID`, `firstName`, `middleName`, `lastName`, `stationlocation`.`exactlocation`
FROM `firefighterinfo`
JOIN `stationlocation` ON `firefighterinfo`.`StationLocation_locationID`=`stationlocation`.`locationID` ORDER BY `firstName`");
echo '<select name="fireman[]" required><option value=""></option>';
while($row = mysql_fetch_array($results))
{
if($row['fighterID'] == $fighterID)
echo '<option selected>'. $row['firstName']." ".$row['middleName']." ".$row['lastName'].", ".$row['exactlocation'].'</option>';
else
echo '<option>'. $row['firstName']." ".$row['middleName']." ".$row['lastName'].", ".$row['exactlocation'].'</option>';
}// end while
echo '</select><br>';
?>
</td>
<td>
<input type="button" value="X" class="removeVar"/>
</td>
</tr>
<?php
$row++;
endforeach;
?>