Question

我正在使用Python及其标准库函数random.choice。我只是想知道，有没有办法得不到相同的结果，例如没有得到"Strawberry"两次。我已经尝试了许多方法，但没有提出任何建议。

我已经包含了我的代码：

#Random selection for for doughnuts
import random
from tkinter import *

Doughnuts = ['Strawberry', 'Apple Cinnamon',
             'Blueberry Blaster', 'Custard', 'Sugar', ...]

def RandomDough():
    for i in range(6):
        print (random.choice(Doughnuts))

app=Tk()
app.title('Your tkinter app')
app.geometry('450x100+200+100')
b1=Button(app, text='Random Special', width = 20, command=RandomDough)
b1.pack(side='right')
app.mainloop()

我甚至尝试使用random.sample，但我想不出如何将int数字转换为实际的单词"Strawberry"：

#Random selection for for doughnuts
import random
from tkinter import *

def RandomDough():
    Doughnuts = random.sample(range(1, 8), 6)
    print (Doughnuts)

app=Tk()
app.title('Your tkinter app')
app.geometry('700x200+200+100')
b1=Button(app,text='Random Special',width = 20,height = 20,command=RandomDough)
b1.pack(side ='right')
app.mainloop()

Answer 1

只需将Doughnuts 列表传递给random.sample();不要使用指数：

Doughnuts = ['Strawberry ','Apple Cinnamon ','Blueberry Blaster ','Custard ','Sugar']
for choice in random.sample(Doughnuts, 6):
    print(choice)

Answer 2

随机播放它们，然后使用或迭代切片...：

from random import shuffle

Doughnuts = ['Strawberry ','Apple Cinnamon ','Blueberry Blaster ','Custard ','Sugar']
shuffle(Doughnuts)
for doughnut in Doughnuts[:6]:
    print doughnut # or whatever

这可以适用于一次选择一个独特的dougnuts，例如：

shuffle(Doughnuts)
items = iter(Doughnuts)
doughnut = next(items) # get 1
# .... other code
another_doughnut = next(items)

Random.choice相同的结果

2 个答案: