Question

我有一个程序可以输入一些关于人的信息。例如：

Surname: Tomson
Forename: Tyler

然后我点击“添加”按钮，它将新人添加到listView。如果我现在重新启动程序，名称会更改。所以必须有“汤姆森泰勒”，但有“泰勒汤臣”。如果我再次重新启动它，它会再次更改名称。所以每次重启都会改变。我不知道为什么。以下是我将代码添加到listView：

的代码

List<People> people = new List<People>();

private void btnAdd_Click(object sender, EventArgs e)
    {
        if(!Directory.Exists(path))
        {
            Directory.CreateDirectory(path);
        }

        if (!File.Exists(path + "\\save.xml"))
        {
            XmlTextWriter xwriter = new XmlTextWriter(path + "\\save.xml", Encoding.UTF8);
            xwriter.WriteStartElement("Root");
            xwriter.WriteEndElement();
            xwriter.Close();
        }

        People p = new People();
        p.Surname = txtSurname.Text;
        p.Forename = txtForename.Text;

        people.Add(p);
        listViewKunden.Items.Add(p.Surname + " " + p.Forename);

        txtSurname.Text = "";
        txtForename.Text = "";
}

class People
{
    public string Surname
    {
        get;
        set;
    }

    public string Forename
    {
        get;
        set;
    }
}

编辑：

我忘了分享加载和保存xml文件的代码。这里是。第一部分用于加载/读取，第二部分用于保存：

private void Form1_Load(object sender, EventArgs e)
{
    System.Xml.XmlDocument xdocument = new System.Xml.XmlDocument();
    xdocument.Load(path + "\\save.xml");
    foreach (XmlNode xnode in xdocument.SelectNodes("Root/People"))
    {
        People p = new People();
        p.Nachname = xnode.SelectSingleNode("Surname").InnerText;
        p.Vorname = xnode.SelectSingleNode("Forename").InnerText;

        people.Add(p);
        listViewKunden.Items.Add(p.Surname + " " + p.Forename);
    }

    using (FileStream rfs = new FileStream(path + "\\save.xml", FileMode.Open, FileAccess.Read))
    {
        System.Xml.XmlDocument doc = new System.Xml.XmlDocument();
        doc.Load(rfs);
    }
}


private void Form1_FormClosing(object sender, FormClosingEventArgs e)
{
    System.Xml.XmlDocument xdoc = new System.Xml.XmlDocument();
    xdoc.LoadXml("<Root></Root>");
    XmlNode xnode = xdoc.SelectSingleNode("Root");
    using(FileStream wfs = new FileStream(path + "\\NewFred.xml",FileMode.Create,FileAccess.Write))
    {
        System.Xml.XmlDocument doc = new System.Xml.XmlDocument();
       doc.Save(wfs);
    }
    foreach (People p in people)
    {
        XmlNode xtop = xdoc.CreateElement("People");
        XmlNode xsurname = xdoc.CreateElement("Surname");
        XmlNode xvorname = xdoc.CreateElement("Forename");

        xsurname.InnerText = p.Forename;
        xforename.InnerText = p.Surname;

        xtop.AppendChild(xsurname);
        xtop.AppendChild(xforename);

        xdoc.DocumentElement.AppendChild(xtop);
    }
    xdoc.Save(path + "\\save.xml");
    e.Cancel = false;
}

Answer 1

你刚刚切换了这些：

xsurname.InnerText = p.Forename;
xforename.InnerText = p.Surname;

他们应该是：

xsurname.InnerText = p.Surname;
xforename.InnerText = p.Forename;

Answer 2

公司必须阅读有关XML序列化和反序列化的内容。属性和类模型中的第二个mising属性。

var serializer = new XmlSerializer(typeof(T));
 using (XmlWriter xmlWriter = XmlWriter.Create(stream, writerSettings))
 {
    serializer.Serialize(xmlWriter, obj);
 }


var serializer = new XmlSerializer(typeof(T));
result = (T)serializer.Deserialize(stream);


[Serializable]
public class Settings


public class TaxRates
{
    [XmlElement(ElementName = "TaxRate")]
    public decimal ReturnTaxRate;
}

Answer 3

检查这个

xsurname.InnerText = p.Forename;
        xforename.InnerText = p.Surname;

如果问题依赖于错误的定位行，那么其他可能的共振并不是非常可靠的分类。

关闭前你必须排序。可能这是你的问题。每次保存/关闭后，您都会更改行的顺序。检查一下。

ListView会在每次重启程序时更改单词值

3 个答案: