Question

首先，我很遗憾可能标题错了。我会解释我的问题。我有一个带有showinputdialog组件的joptionpane来输入服务器地址。我想点击取消按钮后，它将返回主窗口。但在我的情况下，它改为第二个joptionpane。

我的英语不好:) ... 有人可以帮帮我吗？

这是我的代码

    private static int setPortNumber()
{
    String portNumber = JOptionPane.showInputDialog(frame,
            "Enter the Port number for server creation","Server Connection\n",
            JOptionPane.OK_CANCEL_OPTION);
    int PORT = Integer.parseInt(portNumber);

    return PORT;

}   

private static String setServerName()
{   
    server_address = JOptionPane.showInputDialog(frame,
            "Enter Server Address or PC-Name.", "Server Connection",
            JOptionPane.OK_CANCEL_OPTION);
    return server_address;

}

private void networking() {
    server_address = setServerName();
        try {

            PORT = setPortNumber();
            if (server_address != null) {

                sock = new Socket(InetAddress.getByName(server_address) ,
                        PORT);
            } 
            else {
                SocketException sc = new SocketException();
                throw sc;
            }


        // Recieving input and output streams
        InputStreamReader ir = new InputStreamReader(sock.getInputStream());
        br = new BufferedReader(ir);
        pw = new PrintWriter(sock.getOutputStream());
        login.setEnabled(true);
        incoming.append("Connected to Server.please login.\n");
        connect.setEnabled(false);
        pw.println("~##~");
        pw.flush();
        login.requestFocus();
    }

Answer 1

private void networking() {
    server_address = setServerName();
    if(server_address == null || server_address.equals("")){
        //Handle what happens when the server name is empty (or the user clicked the cancel button. If you let the execution continue, then the try/catch block below will pop up the second jInputDialog
    }
        try {

            PORT = setPortNumber();
            if (server_address != null) {

                sock = new Socket(InetAddress.getByName(server_address) ,
                    PORT);
            } 
            else {
                SocketException sc = new SocketException();
                throw sc;
            }
...
}

Answer 2

运行此示例。它工作正常

import javax.swing.JOptionPane;


public class NetWorking {

    public static String server_address;
    public static void main(String[] args) {
        networking();

    }

       private static int setPortNumber()
       {
           String portNumber = JOptionPane.showInputDialog(null,
                   "Enter the Port number for server creation","Server Connection\n",
                   JOptionPane.OK_CANCEL_OPTION);
           int PORT = Integer.parseInt(portNumber);

           return PORT;

       }   

       private static void setServerName()
       {   
           server_address = JOptionPane.showInputDialog(null,
                   "Enter Server Address or PC-Name.", "Server Connection",
                   JOptionPane.OK_CANCEL_OPTION);

       }

       private static void networking(){
           setServerName();
           if (server_address == null) {
               return;
           } 
            Integer  port = setPortNumber();
            if (port != null) {
                System.out.println(port);
            }
       }

}

在两个JOptionPane showInputDialog中处理java取消按钮

2 个答案: