如何将mongo文档与一系列规则逐一匹配

时间:2014-01-03 06:38:25

标签: javascript mongodb rule-engine

我找了一个并找回一份文件。我也有一套mongo规则。我需要根据这组规则匹配文档,如果文档与规则匹配,请将规则的名称附加到规则名称子文档。

假设文件是​​这个 -

var randomGuy = { name: "Random Guy", age: 45, state: "assam", profession: "coder", ruleNames: [] };

我将它存储在JavaScript变量中。我也有一套规则,转换为mongodb规则 -

var rules = [
       {'rule1': { name: /R*/i, age: { $gt: 40 } }},
       {'rule2': { state: "karnataka" }},
       {'rule3': { age: { $lt: 60 } }},
       {'rule4': { $or: [ { profession: 'coder' }, { profession: 'programmer' } ] }}
    ];

我想循环遍历规则,将randomGuy对象与每个规则匹配,并将规则名称附加到randomGuy的ruleNames属性。所以最终的randomGuy对象看起来像这样 -

var randomGuy = { name: "Random Guy", age: 45, state: "assam", profession: "coder", ruleNames: ['rule1', 'rule3', 'rule4'] };

1 个答案:

答案 0 :(得分:2)

我想我在sift.js中找到了答案 - https://github.com/crcn/sift.js

我需要做的就是将规则作为筛选过滤器应用于randomGuy对象。

var randomGuys = [randomGuy];
var ruleName, ruleString;
rules.forEach(function(rule) {
    ruleName = Object.keys(rule)[0];
    ruleString = rule[ruleName];
    if(sift(ruleString).test(randomGuy)) {
        randomGuys.ruleNames.push(ruleName);
    }
}