Question

以下MySQL查询结果显示每个帐户代码（acctcode）的贷记和借记总和，并使用union all生成总计。表ledg_post有570万条记录并已编入索引。查询还需要1分钟才能执行。请帮我调整一下这个问题。

select b.acnt_code as acctcode 
,      b.disp_name as acctname
,      sum(amt_dr) as debit
,      sum(amt_cr) as credit
,      (sum(amt_dr)- sum(amt_cr)) as closingbalance
,      a.txn_code as txn_code
from   ledg_post a
,      gl_acnts b
,      mst_loan lmt
where  a.acnt_code = b.acnt_code 
group 
by     b.acnt_code
union all
select  ' ' acctcode
,       ' Grand Total ' acctname
,       sum(amt_dr) debit
,       sum(amt_cr) credit
,       (sum(amt_dr)- sum(amt_cr)) closingbalance
,       '' txn_code
from    ledg_post a
,       mst_loan  lmt
where   lmt.loan_id = a.ref_id

表定义

 create table ledg_post 
 ( txn_code  int(11) 
 , ref_id    int(11)
 , acnt_code int(11) 
 , amt_dr    decimal(20, 2) 
 , amt_cr    decimal(20, 2) 
 );

 create table gl_acnts 
 ( glm_acnt_code      int
 , glm_acnt_disp_name varchar(50) 
 );

 create table mst_loan 
 ( lmt_loan_id int(11) 
 , lmt_clnt_id int(11) 
 );

Answer 1

无需使用UNION ALL，您可以使用GROUP BY ... WITH ROLLUP

来实现此目的

试试这个：

SELECT b.acnt_code AS acctcode, IFNULL(b.disp_name, ' Grand Total ') AS acctname, 
       SUM(a.amt_dr) AS debit, SUM(a.amt_cr) AS credit, 
      (SUM(a.amt_dr)- SUM(a.amt_cr)) AS closingbalance, 
       IFNULL(a.txn_code, '') AS txn_code
FROM ledg_post a 
INNER JOIN gl_acnts b ON a.acnt_code=b.acnt_code 
GROUP BY acctcode WITH ROLLUP

如何调整UNION ALL查询？

表定义

1 个答案: