Question

         <tbody id="ajax_fresh">
       <?php
            $p_id=$_GET["p_id"];
        $k=1;
        $i = 1;
        $sql_pdetails="select * from tb_party_rate_entry where party_id='$p_id'";
         $query_pdetails=mysql_query($sql_pdetails);
        while($row_pdetails=mysql_fetch_array($query_pdetails))
        {


       ?>

        <tr >
        <td><?php echo $i++ ; ?></td>


            <td>  <input type="text" style="width:100px; height:22px; float:left; margin:0px 0px 0px 0px;" name="new_price[]" class="new_price" id="newprice<?php echo $i;?>" rel="<?php echo $i;?>" value="<?php echo $row_pdetails["price"]; ?>" /></td>
        <td><input type="text" style="width:70px; height:22px; float:left; margin:0px 0px 0px 0px;" name="org_price[]" class="" value="<?php echo $row_pdetails["org_price"]; ?>" readonly/></td>
         <td><input type="text" style="width:70px; height:22px; float:left; margin:0px   0px 0px 0px;" name="yield" class=""  value="<?php echo $row_pdetails["yield"]; ?>"/></td>
                    <td></td>

              </tr>

         <?php
         $i++;
           } ?>
         </tbody>

这个PHP代码正在获取值并显示id的数据....现在在这个表的顶部我已经应用了一个选择框，我希望每当我从该选择框中选择一个id然后它应该显示对应于那个id的数据..为此我已经应用了像这样的onchange事件....

          <option value="">Select Rate Type</option>
            <?php
        $sql_party_name="select * from tb_party";
      $query_party_name=mysql_query($sql_party_name);
        while($row_party_name=mysql_fetch_array($query_party_name))
        {
        ?>

       <option value='<?php echo $row_party_name["party_id"]; ?>'><?php echo     $row_party_name["party_name"]; ?> </option>
            <?php } ?>
          </select>

       the ajax code is as follows..

            <script type="text/javascript">
         function data(id)

      {
 if (window.XMLHttpRequest)
     {// code for IE7+, Firefox, Chrome, Opera, Safari
             xmlhttp=new XMLHttpRequest();
       }
           else
            {// code for IE6, IE5
        xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
       }
         xmlhttp.onreadystatechange=function()
           {
       if (xmlhttp.readyState==4 && xmlhttp.status==200)
              {

         document.getElementById("ajax_fresh").innerHTML=xmlhttp.responseText;

             }
              }

       xmlhttp.open("GET","ajax/getinfo.php?cat_id="+id,true);
          xmlhttp.send();

             }

           </script>



        the page where ajax is going is
          <tbody id="ajax_fresh">

         <?php
          $p_id=$_GET["cat_id"];
            $k=1;
           $i = 1;
           $sql_pdetails="select * from tb_party_rate_entry where party_id='$p_id'";
        $query_pdetails=mysql_query($sql_pdetails);
            while($row_pdetails=mysql_fetch_array($query_pdetails))
         {


       ?>

       <tr>

        <td><?php echo $k++ ; ?></td>



    <td><input type="text" style="width:100px; height:22px; float:left; margin:0px 0px 0px 0px;" name="new_price[]" class="new_price" id="newprice<?php echo $i;?>" rel="<?php echo $i;?>" value="<?php echo $row_pdetails["price"]; ?>" /></td>
     <td><input type="text" style="width:70px; height:22px; float:left; margin:0px 0px 0px 0px;" name="org_price[]" class="" value="<?php echo $row_pdetails["org_price"]; ?>" readonly/></td>
     <td><input type="text" style="width:70px; height:22px; float:left; margin:0px 0px  0px 0px;" name="yield" class=""  value="<?php echo $row_pdetails["yield"]; ?>"/></td>
      <td></td>

        </tr>


        <?php } ?>
        </tbody>

当我从选择框中选择一个选项...它会显示与其对应的值但是当我点击按钮更新时，它应该插入使用ajax加载的值....但是当我点击时更新按钮....它没有插入任何值...我想插入当我调用ajax时已加载的值...这是我的代码...请帮助我...

通过ajax调用的值没有得到更新

0 个答案: