Question

在我的应用程序中，我想检查用户是否输入了有效的卡号，因为我使用了LUHN算法。我已将其创建为方法并在mainactivity中调用。但即使我提供有效的卡号，它也显示无效。虽然输入卡号我之间给出了空格我不知道因为它没有正确验证。请帮助我找出错误。

CreditcardValidation.java

public class CreditcardValidation {
    String creditcard_validation,msg;
    //String mobilepattern;
     public static boolean isValid(long number) {

            int total = sumOfDoubleEvenPlace(number) + sumOfOddPlace(number);
            if ((total % 10 == 0) && (prefixMatched(number, 1) == true) && (getSize(number)>=16 ) && (getSize(number)<=19 )) {
                return true;
            } else {
                return false;
            }
        }

        public static int getDigit(int number) {

            if (number <= 9) {
                return number;
            } else {
                int firstDigit = number % 10;
                int secondDigit = (int) (number / 10);

                return firstDigit + secondDigit;
            }
        }
        public static int sumOfOddPlace(long number) {
            int result = 0;

            while (number > 0) {
                result += (int) (number % 10);
                number = number / 100;
            }

            return result;
        }

        public static int sumOfDoubleEvenPlace(long number) {

            int result = 0;
            long temp = 0;

            while (number > 0) {
                temp = number % 100;
                result += getDigit((int) (temp / 10) * 2);
                number = number / 100;
            }

            return result;
        }

        public static boolean prefixMatched(long number, int d) {

            if ((getPrefix(number, d) == 5)
                    || (getPrefix(number, d) == 4)
                    || (getPrefix(number, d) == 3)) {

                if (getPrefix(number, d) == 4) {
                    System.out.println("\nVisa Card ");
                } else if (getPrefix(number, d) == 5) {
                    System.out.println("\nMaster Card ");
                } else if (getPrefix(number, d) == 3) {
                    System.out.println("\nAmerican Express Card ");
                }

                return true;

            } else {

                return false;

            }
        }

        public static int getSize(long d) {

            int count = 0;

            while (d > 0) {
                d = d / 10;

                count++;
            }

            return count;

        }

        public static long getPrefix(long number, int k) {

            if (getSize(number) < k) {
                return number;
            } else {

                int size = (int) getSize(number);

                for (int i = 0; i < (size - k); i++) {
                    number = number / 10;
                }

                return number;

            }

        }


        public String creditcardvalidation(String creditcard)
        {       
             Scanner sc = new Scanner(System.in);

              this.creditcard_validation= creditcard;
              long input = 0;
             input = sc.nextLong();
            //long input = sc.nextLong();
               if (isValid(input) == true) {
                   Log.d("Please fill all the column","valid");
                msg="Valid card number";

               }
               else{
                   Log.d("Please fill all the column","invalid");
                msg="Please enter the valid card number";

               }

               return msg;
} 
} 


MainActivity.java

addcard.setOnClickListener(new OnClickListener() 
{   
    @Override
    public void onClick(View v) {


            if(v.getId()==R.id.btn_add)
            {
                creditcard= card_number.getText().toString();
                cv = new  CreditcardValidation();
                String mob = cv.creditcardvalidation(creditcard);
                 Toast.makeText(getActivity(), mob, 1000).show();``

Answer 1

参考下面的代码

 EditText cardNumber=(EditText)findViewById(R.id.cardNumber);
        String CreditCardType = "Unknown";

       /// Remove all spaces and dashes from the passed string
        String CardNo ="9292304336";///////cardNumber.getText().toString();           
        CardNo = CardNo.replace(" ", "");//removing empty space
             CardNo = CardNo.replace("-", "");//removing '-'
              twoDigit=Integer.parseInt(CardNo.substring(0, 2));
                                 System.out.println("----------twoDigit--"+twoDigit);
              fourDigit=Integer.parseInt(CardNo.substring(0, 4));
                                 System.out.println("----------fourDigit--"+fourDigit);
             oneDigit=Integer.parseInt(Character.toString(CardNo.charAt(0)));
                                System.out.println("----------oneDigit--"+oneDigit);

             boolean cardValidation=false;
            // 'Check that the minimum length of the string isn't <14 characters and -is- numeric
             if(CardNo.length()>=14)
             {

                 cardValidation=cardValidationMethod(CardNo);

             }

 boolean cardValidationMethod(String CardNo)
     {
        //'Check the first two digits first,for AmericanExpress
        if(CardNo.length()==15 && (twoDigit==34 || twoDigit==37))
        return true;
        else
            //'Check the first two digits first,for MasterCard
            if(CardNo.length()==16 && twoDigit>=51 && twoDigit<=55)
                return true;
        else
            //'None of the above - so check the 'first four digits collectively
                if(CardNo.length()==16 && fourDigit==6011)//for DiscoverCard
                return true;
        else

            if(CardNo.length()==16 || CardNo.length()==13 && oneDigit==4)//for VISA
                return true;
            else
                return false;       
     }

你也可以参考这个演示project

Answer 2

Scanner.nextLong()将停止阅读，因为遇到空格（或其他非数字字符）。

例如，如果输入为1234 567 ..，那么nextLong()将仅读取1234。

然而，虽然信用卡中的空间[可能]会导致它使用上面的代码失败LUHN验证，但我不保证删除空格会使它通过 - 我会使用更强大（并且很好） -tested）从一开始就实现。没有必要重写这样的代码。

LUHN信用卡验证因有效卡号而失败

2 个答案: