Question

目前正致力于从我返回的JSON数据中创建新的NSMutableDictionary。我想提取：tide.tideSummary.data.type和tide.tideSummary.date.epoch - 我想用这两个键创建一个新的字典数组。

以下是我现在的情况：

for (NSDictionary *dict in self.tideSummary) {

NSString *type = [self.tideSummary valueForKeyPath:@"data.type"];
NSString *date = [self.tideSummary valueForKeyPath:@"date.epoch"];

[sunCycleDictionary setValue:(type) forKey:@"type"];
[sunCycleDictionary setValue:(date) forKey:@"epoch"];
}

现在我的NSLog完全返回每个键。截至目前的示例日志，不正确

 epoch =     (
    1388724761,
    1388746063,
    ...

我的目标是制作此输出： - 一系列词典。

 {
 type: Sunrise,
 epoch: 1336116677
 },
 {
 type: Sunset,
 epoch: 1336116677
 },
 {
 type: Moonset,
 epoch: 1336116677
 },
 ...

我认为我非常接近，我只需要在他们自己的对象中加入这两个键值对。 我需要为之前创建的词典创建NSMutableArray和addObject吗？

我正在使用的数据：

"tideSummary": [
            {
                "date": {
                    "pretty": "11:58 AM PST on December 19, 2013",
                     ...
                    "epoch": "1387483136"
                },
                "utcdate": {
                    "pretty": "7:58 PM GMT on December 19, 2013",
                    ...
                    "epoch": "1387483136"
                },
                "data": {
                    "height": "5.97 ft",
                    "type": "High Tide"
                }
            },

关于如何实现这一目标的想法？

Answer 1

你非常接近你的输出，但显示的输出不完全字典它是一个字典数组，所以你需要做这样的事情。

    NSMutableArray *finalOutput = [[NSMutableArray alloc] init]; //Add this

    for (NSDictionary *dict in self.tideSummary)
    {
        NSMutableDictionary *sunCycleDictionary = [[NSMutableDictionary alloc] init]; //Add this

        NSString *type = [self.tideSummary valueForKeyPath:@"data.type"];
        NSString *date = [self.tideSummary valueForKeyPath:@"date.epoch"];

        [sunCycleDictionary setValue:(type) forKey:@"type"];
        [sunCycleDictionary setValue:(date) forKey:@"epoch"];

        [finalOutput addObject: sunCycleDictionary]; //Add this

    }

    NSLog(@"out of loop: %@", finalOutput);

Answer 2

试试这个

NSMutableArray *outputArray = [[NSMutableArray alloc] init];

for (NSDictionary *dict in self.tideSummary)
{
    NSMutableDictionary *sunCycleDictionary = [[NSMutableDictionary alloc] init];

    NSString *type = [dict valueForKeyPath:@"data.type"];
    NSString *date = [dict valueForKeyPath:@"date.epoch"];

    [sunCycleDictionary setValue:(type) forKey:@"type"];
    [sunCycleDictionary setValue:(date) forKey:@"epoch"];

    [outputArray addObject:sunCycleDictionary];

}

NSLog(@"output array : %@", outputArray);

Answer 3

Try This

NSMutableArray *temp =[[NSMutableArray alloc]init];
for (NSDictionary *dict in self.tideSummary) {

NSString *type = [self.tideSummary valueForKeyPath:@"data.type"];
NSString *date = [self.tideSummary valueForKeyPath:@"date.epoch"];
NSLog(@"type: %@", type);

[sunCycleDictionary setValue:(type) forKey:@"type"];
[sunCycleDictionary setValue:(date) forKey:@"epoch"];
[temp addObject: sunCycleDictionary];
NSLog(@"in loop: %@", temp);
}

Answer 4

            int i=0;
            while (i<[_arayResjoBID count]) {

                NSLog(@"%d",i);
                NSDictionary *dict=[[NSMutableDictionary alloc]init];

                [dict setValue:[[_arayResjoBID objectAtIndex:i]valueForKeyPath:@"BarCode"] forKey:@"barcode"];
                [dict setValue:[[_arayResjoBID objectAtIndex:i] valueForKeyPath:@"ItemName"] forKey:@"itemname"];
                [dict setValue:[[_arayResjoBID objectAtIndex:i] valueForKeyPath:@"Quantity"] forKey:@"quantity"];
                [dict setValue:@"NO"  forKey:@"Yes"];

                [_arayFilter insertObject:dict atIndex:i];

                i++;
            }
        }

        NSLog(@"%@",_arayFilter);
        [self.tableView reloadData];

OUTPUT：在调试区域（ { 是=否; 条形码= 1002690094467; itemname =“Box Oversized 100X80x80”; 数量= 5; }， { 是=否; 条形码= 1002690094474; itemname =“道路案例大”; 数量= 2; }， { 是=否; 条形码= 1002690094481; itemname =“Road Case New Double”; 数量= 4; } ）

使用现有数组中的字典创建新数组（提取特定键值路径）

4 个答案: