到目前为止,我已经开始了一两个线程,但没有解决任何问题。我无法使用mysqlnd,因为我正在使用godaddy的共享主机帐户。
我需要做的就是检查我的电子邮件地址和/或用户名是否正在使用中;如果他们在使用投掷和错误,如果没有..一切都很好。
这是我的代码:
$input_errors = array();
if (!empty($_POST['username'])) {
$user = $_POST['username'];
} else {
$input_errors['username'] = "Must fill out username";
}
$email = filter_input(INPUT_POST, 'usermail', FILTER_VALIDATE_EMAIL);
if (false === $email) {
$input_errors['usermail'] = "Not a valid email address";
}
if(count($input_errors) > 0) {
print_r($input_errors); die();
}
$sql = "SELECT COUNT(*) as amount FROM people WHERE username = ?
OR email = ?";
if ($stmt = $mysqli->prepare($sql)) {
$stmt->bind_param("ss", $user, $email);
$stmt->execute();
$results = $stmt->get_result();
$data = mysqli_fetch_assoc($results);
if ($data['amount'] > 0)
{
print "User already exists";
}
}
else {
$stmt = $mysqli->stmt_init();
if (!$stmt) {
echo "Init failed";
} else {
$cmd = "INSERT INTO people (username, email, sign_up_date) VALUES (?, ?, NOW() )";
if ($stmt->prepare($cmd)) {
$stmt->bind_param('ss', $user, $email );
$stmt->execute();
echo $stmt->affected_rows . " row(s) inserted";
$stmt->close();
} else {
echo "Prepare failed";
}
mysqli_close($mysqli);
}
}
bind_result()
不起作用。
答案 0 :(得分:0)
将sql语句更改为以下内容:
$sql = "SELECT COUNT(*) as amount FROM people WHERE username = '".mysqli_real_escape_string($_POST['username'])."' OR email = '".mysqli_real_escape_string($email)."'";