Question

我有一个类似于下面的NSMutableArray，想要查看并删除具有相同realLocationName和ADD_LINE1的对象并保留realLocationName对象。

我的阵列现在：

(
        {
        locationId = "12-11-2013 10:23:53";
        realLocationName = wauk;
    },
        {
        locationId = "01-02-2014 10:10:11";
        realLocationName = sdf;
    },
        {
        locationId = "01-02-2014 11:55:49";
        realLocationName = "514 COURT AVE";
    },
        {
        "ADD_CITY" = city;
        "ADD_LINE1" = "514 COURT AVE";
        "ADD_LINE2" = "";
        "ADD_STATE" = IA;
        "ADD_ZIP" = 50833;
        "BUSINESS_NAME" = "";
        "FIRST_NAME" = joe;
        "LAST_NAME" = smith;
    },
        {
        "ADD_CITY" = cty2;
        "ADD_LINE1" = "514 COURT AVE";
        "ADD_LINE2" = "";
        "ADD_STATE" = IA;
        "ADD_ZIP" = 50833;
        "BUSINESS_NAME" = "";
        "FIRST_NAME" = randy;
        "LAST_NAME" = red;
    }
)

我想要的是什么：

(
        {
        locationId = "12-11-2013 10:23:53";
        realLocationName = wauk;
    },
        {
        locationId = "01-02-2014 10:10:11";
        realLocationName = sdf;
    },
        {
        locationId = "01-02-2014 11:55:49";
        realLocationName = "514 COURT AVE";
    }
)

修改

或这种情况： array =

(
            {
            locationId = "12-11-2013 10:23:53";
            realLocationName = wauk;
        },
            {
            locationId = "01-02-2014 10:10:11";
            realLocationName = sdf;
        },
            {
            "ADD_CITY" = city;
            "ADD_LINE1" = "514 COURT AVE";
            "ADD_LINE2" = "";
            "ADD_STATE" = IA;
            "ADD_ZIP" = 50833;
            "BUSINESS_NAME" = "";
            "FIRST_NAME" = joe;
            "LAST_NAME" = smith;
        },
            {
            "ADD_CITY" = cty2;
            "ADD_LINE1" = "514 COURT AVE";
            "ADD_LINE2" = "";
            "ADD_STATE" = IA;
            "ADD_ZIP" = 50833;
            "BUSINESS_NAME" = "";
            "FIRST_NAME" = randy;
            "LAST_NAME" = red;
        }
    )

并获取此信息：

(
            {
            locationId = "12-11-2013 10:23:53";
            realLocationName = wauk;
        },
            {
            locationId = "01-02-2014 10:10:11";
            realLocationName = sdf;
        },
            {
            "ADD_CITY" = city;
            "ADD_LINE1" = "514 COURT AVE";
            "ADD_LINE2" = "";
            "ADD_STATE" = IA;
            "ADD_ZIP" = 50833;
            "BUSINESS_NAME" = "";
            "FIRST_NAME" = joe;
            "LAST_NAME" = smith;
        }
    )

Answer 1

您可以使用集合（NSMutableSet）来检查是否添加了realLocationName。

此代码如何运作？

1）每个对象，我得到“realLocationName”键或“ADD_LINE1”键的值，假设没有对象同时具有这两个键，但肯定存在一个键

2）数组被命令所有“realLocationName”对象都在开头部分 - 这是因为要求具有realLocationName的对象优先于具有ADD_LINE1的对象。

NSMutableArray *arr_noduplicates = [NSMutableArray array];
NSMutableSet *set_of_already_added = [NSMutableSet set];

for (NSDictionary *obj in originalArray) {
    NSString *str_value = [NSString stringWithFormat:@"%@%@", 
                          obj[@"realLocationName"] ? obj[@"realLocationName"] : @"", 
                          obj[@"ADD_LINE1"] ? obj[@"ADD_LINE1"] : @""];
    if (![set_of_already_added containsObject:str_value]) {
        [arr_noduplicates addObject:obj];
        [set_of_already_added addObject:str_value];
    }
}

Answer 2

由于删除对象不是NSMutableArray上最便宜的操作，您可以创建另一个返回NSMutableArray对象的方法，作为属性，它将接收原始数组。

-(NSMutableArray*)filterArray:(NSMutableArray*)originalArray

一开始，新数组将为空。如果任何有趣的属性到目前为止在数组中的对象中，您将在新数组的末尾添加新对象。您将重复此算法，但不会到达原始数组的末尾。

Answer 3

试试这个，它可能对你有帮助。我没有测试它..

mainArray是您的数据。 finalArray是我们要添加过滤器对象的新mutable array。

for (NSDictionary *dict in mainArray) {
    if ([finalArray count] == 0) {
        [finalArray addObject:dict];
    }
    else {

        BOOL isStored = NO;

        for (NSDictionary *newDict in finalArray) {
            if ([newDict[@"realLocationName"] isEqualToString:dict[@"realLocationName"]] || [newDict[@"ADD_LINE1"] isEqualToString:dict[@"ADD_LINE1"]] ) {//Check first ADD_LINE1 value is there or not? then go with this condition
                isStored = YES;
                break;
            }
        }

        if (!isStored) {
            [finalArray addObject:dict];
        }
    }
}

循环遍历nsmutablearray并删除重复的对象

3 个答案: