我在Assembler中的代码有问题。我有这些秒表。通过按下按钮1，它将开始计数，再次按下它将暂停计数，按下按钮2，它将复位，并通过翻转开关编号1，它将开始递减当前的值。但我现在需要使用按钮编号3，而不是开关编号1.我编程后已经有一段时间了。请问有人可以帮帮我吗？感谢
VHDL "ROM_blank.vhd", "ProgMem.vhd", "ProgMem"
BUTTON DSIN $00
SWITCH DSIN $01
LED DSOUT $02
SEG0 DSOUT $03
SEG1 DSOUT $04
SEG2 DSOUT $05
SEG3 DSOUT $06
wait0 equ s0
wait1 equ s1
wait2 equ s2
cnt0 equ s3
cnt1 equ s4
cnt2 equ s5
cnt3 equ s6
state equ s7
segsel equ s8
temp equ sf
updown equ s9
state_r0 equ 0
state_r1 equ 1
state_s0 equ 2
state_s1 equ 3
decoded_dp equ 254
decoded_0 equ 3
decoded_1 equ 159
decoded_2 equ 37
decoded_3 equ 13
decoded_4 equ 153
decoded_5 equ 73
decoded_6 equ 65
decoded_7 equ 27
decoded_8 equ 1
decoded_9 equ 25
decoded_A equ 5
decoded_B equ 193
decoded_C equ 229
decoded_D equ 133
decoded_E equ 97
decoded_F equ 113
init:
load cnt0, 0
load cnt1, 0
load cnt2, 0
load cnt3, 0
load state, state_s0
start:
; read buttons
in temp, BUTTON
; reset check
and temp, 2
jump z, startstop_check
load cnt0, 0
load cnt1, 0
load cnt2, 0
load cnt3, 0
startstop_check:
in temp, BUTTON
and temp, 1
; state machine
comp state, state_r0
jump z,run0
comp state, state_r1
jump z,run1
comp state, state_s0
jump z, stop0
comp state, state_s1
jump z, stop1
load state, state_s0
stop0:
comp temp, 1
jump nz, fsm_end
load state, state_r0
jump fsm_end
run0:
comp temp, 0
jump nz, fsm_end
load state, state_r1
jump fsm_end
run1:
comp temp, 1
jump nz, fsm_end
load state, state_s1
jump fsm_end
stop1:
comp temp, 0
jump nz, fsm_end
load state, state_s0
fsm_end:
;wait 0.01s
call waitfcn
comp state, state_s0
jump z, decode
comp state, state_s1
jump z, decode
in updown, SWITCH
comp updown, 1
jump z, odecitej
add cnt0, 1
comp cnt0, 10
jump nz, decode
load cnt0, 0
add cnt1, 1
comp cnt1, 10
jump nz, decode
load cnt1, 0
add cnt2, 1
comp cnt2, 10
jump nz, decode
load cnt2, 0
add cnt3, 1
comp cnt3, 10
jump nz, decode
load cnt3, 0
call decode
odecitej:
sub cnt0, 1
comp cnt0, 255
jump nz, decode
load cnt0, 9
sub cnt1, 1
comp cnt1, 255
jump nz, decode
load cnt1, 9
sub cnt2, 1
comp cnt2, 255
jump nz, decode
load cnt2, 9
sub cnt3, 1
comp cnt3, 255
jump nz, decode
load cnt3, 9
decode:
;decode for output
load temp, cnt0
call decodefcn
out temp, SEG0
load temp, cnt1
call decodefcn
out temp, SEG1
load temp, cnt2
call decodefcn
;add decimal point
and temp, 254
out temp, SEG2
load temp, cnt3
call decodefcn
out temp, SEG3
jump start
decodefcn:
comp temp, 0
jump nz, dec1
load temp, decoded_0
ret
dec1:
comp temp, 1
jump nz, dec2
load temp, decoded_1
ret
dec2:
comp temp, 2
jump nz, dec3
load temp, decoded_2
ret
dec3:
comp temp, 3
jump nz, dec4
load temp, decoded_3
ret
dec4:
comp temp, 4
jump nz, dec5
load temp, decoded_4
ret
dec5:
comp temp, 5
jump nz, dec6
load temp, decoded_5
ret
dec6:
comp temp, 6
jump nz, dec7
load temp, decoded_6
ret
dec7:
comp temp, 7
jump nz, dec8
load temp, decoded_7
ret
dec8:
comp temp, 8
jump nz, dec9
load temp, decoded_8
ret
dec9:
load temp, decoded_9
ret
waitfcn:
load wait2, 25
wt0:
load wait1, 25
wt1 :
load wait0, 200
wt2 :
sub wait0, 1
jump nz, wt2
sub wait1, 1
jump nz, wt1
sub wait2, 1
jump nz, wt0
ret
END
答案 0 :(得分：1)
就像我说的那样，您可以通过用第二个按钮替换开关来改变它。
您可以将重置移至button3 - 可能 - 通过：
; reset check
and temp, 4
添加两个新的开关状态和“状态变量”：
switch_state0 equ 0
switch_state1 equ 1
...
switch_state equ s? ; Whichever fits you best
和
startstop_check:
in temp, BUTTON
and temp, 3 ; mask extra bits off
comp temp, 2 ; check if button 2 only
jump nz,button1_check ; no
comp temp, 3 ; check if buttons 1 and 2
jump nz,button1_check ; no
; button 2 was pressed - "simulate" switch
comp switch_state switch_state0 ; still being pressed
jump nz button1_check ; yes - don't toggle
load switch_state switch_state0 ; no, mark new press
xor updown 1 ; toggle switch
button1_check:
comp switch_state switch_state0 ; "switch"-button been pressed
jump nz button1_check ; don't toggle
load switch_state switch_state1 ; mark "switch"-button released
and temp, 1
...
然后，放弃这个：
in updown, SWITCH
也许这有帮助？