Question

我根据在变量$now

中输入的特定日期返回查询时遇到问题

以下是我的代码：

<?php
error_reporting(E_ALL); ini_set('display_errors', 1);
// bind column to variable
//Connect to DB
$host = "localhost"; //Host Name
$port = '3306'; //Default MySQL Port
$dbname = "mama"; //Database Name
$db_username = "root"; //MySQL Username
$db_password = ""; //MySQL Password

$dsn = "mysql:host=$host;port=$port;dbname=$dbname"; //Data Source Name = Mysql
$db = new PDO($dsn, $db_username, $db_password); //Connect to DB

$db->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);

try {
  $now = "2014-01-01";

  //foreach ($query=$db->query("SELECT * FROM log WHERE log_datetime <= :now") as $row) {print_r($row);}
  $query->bindParam(':now', $now, PDO::PARAM_STR);
  $success = $query->execute();
}
// Catch any exception thrown
catch (PDOException $e) {
  echo "Error: " . $e->getMessage();
  // Exit, redirect, whatever you need to do.
}
$rows = $query->fetchAll(PDO::FETCH_OBJ);

?>
<!DOCTYPE HTML>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<style type="text/css">
table, td {
  border: 1px solid black;
  border-collapse: collapse;
}
</style>
<title>Test</title>
</head>

<body>

<table>
    <th>Id</th>
    <th>DOB</th>
    <th>Visit</th>
    <th>Qty</th>
    <th>Amount</th>
<?php
// Use a foreach over $rows
foreach ($rows as $row) {

    // Using htmlspecialchars() on these as good practice for HTML escaping
    // Since they were fetched via FETCH_OBJ access them as properties with ->
    echo '<tr>';
    echo '<td>' . htmlspecialchars($row->log_id) . '</td>';
    echo '<td>' . htmlspecialchars($row->dob) . '</td>';
    echo '<td>' . htmlspecialchars($row->log_datetime) . '</td>';
    echo '<td>' . htmlspecialchars($row->log_count) . '</td>';
    echo '<td>' . htmlspecialchars($row->amount) . '</td>';
    echo '</tr>';
}

?>
</table>
</body>
</html>

我希望结果显示在特定的日期设置上，但除了表头之外什么也不返回。

其他信息，我的log_datetime使用DATETIME mysql格式。

我做了一些SO搜索，但没有在SO中发布的问题或答案可以帮助我的问题。请告诉我哪里出错了，我按照php PDO教程进行了操作，但似乎没有用。

Answer 1

您的SQL语法中有一个小错误：

SELECT * FROM log WHERE log_datetime <= ?
// ----------------------------------^

Answer 2

错误是在sql语法中，尝试更改 "SELECT * FROM log WHERE log_datetime = < ?" 同 "SELECT * FROM log WHERE log_datetime <= ?"

Answer 3

当您开始按顺序检查错误时，这将以一种有意义的方式开始形成。

您的查询执行是正确的，SQL语句本身应该返回预期的值。您的问题仍然在于将值从提取的$row错误地传输到<td>标记中的最终位置。

要注意的一些事情：

Set PDO into ERRMODE_EXCEPTION因此会在任何错误上抛出异常。
将try/catch中的所有数据库内容包装起来以捕获任何PDO异常
使用htmlspecialchars()转义HTML的所有输出
您可以在catch {}区块

require('./inc/connection.php');

// Suggest setting PDO into ERRMODE_EXCEPTION so it throws exceptions on any error
$db->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);

// With PDO in exception mode, wrap all of this in try/catch
try {
  $now = "2014-01-01";

  $query = $db->prepare("SELECT * FROM log WHERE log_datetime <= :now");
  $query->bindParam(':now', $now);
  $success = $query->execute();
}
// Catch any exception thrown
catch (PDOException $e) {
  echo "Error: " . $e->getMessage();
  // Exit, redirect, whatever you need to do.
}

// Assuming no failure (you didn't exit or redirect)
// You can build your table.

// First fetch all rows:
$rows = $query->fetchAll(PDO::FETCH_OBJ);

// Now all your rows are in the array. You're done with PDO.
echo '<table>';
echo '<tr>
<th>Id</th>
<th>DOB</th>
<th>Visit</th>
<th>Qty</th>
<th>Amount</th>
</tr>';

// Use a foreach over $rows
foreach ($rows as $row) {

    // Using htmlspecialchars() on these as good practice for HTML escaping
    // Since they were fetched via FETCH_OBJ access them as properties with ->
    echo '<tr>';
    echo '<td>' . htmlspecialchars($row->log_id) . '</td>';
    echo '<td>' . htmlspecialchars($row->dob) . '</td>';
    echo '<td>' . htmlspecialchars($row->log_datetime) . '</td>';
    echo '<td>' . htmlspecialchars($row->log_count) . '</td>';
    echo '<td>' . htmlspecialchars($row->amount) . '</td>';
    echo '</tr>';
}
echo '</table>';

// You're done.

我删除了内联style-属性的所有。这些都不属于您的标记，而应该在CSS中。它可以用CSS规则处理，如：

table, td {
  border: 1px solid black;
  border-collapse: collapse;
}

关于$now的最后一点说明：如果您真的打算使用当前日期，则不需要绑定参数。您可以直接在语句中调用MySQL的CURDATE()：

SELECT * FROM log WHERE log_datetime <= CURDATE()

Answer 4

while ($query->fetchAll()) {
    echo '<tr>';
    echo '<td style="border: 1px solid black;">' . $log_id . '</td>';
    echo '<td style="border: 1px solid black;">' . $dob . '</td>';
    echo '<td style="border: 1px solid black;">' . $log_datetime . '</td>';
    echo '<td style="border: 1px solid black;">' . $log_count . '</td>';
    echo '<td style="border: 1px solid black;">' . $amount . '</td>';
    echo '</tr>';
}

这不会取任何东西，你需要像

那样重写它

while ($row=$query->fetch(PDO::FETCH_OBJ)) {
 $log_id         = $row->log_id;
    $dob            = $row->dob;
    $log_datetime   = $row->log_datetime;
    $log_count      = $row->log_count;
    $amount         = $row->amount;

    echo '<tr>';
    echo '<td style="border: 1px solid black;">' . $log_id . '</td>';
    echo '<td style="border: 1px solid black;">' . $dob . '</td>';
    echo '<td style="border: 1px solid black;">' . $log_datetime . '</td>';
    echo '<td style="border: 1px solid black;">' . $log_count . '</td>';
    echo '<td style="border: 1px solid black;">' . $amount . '</td>';
    echo '</tr>';
}

php pdo获取特定日期的数据返回空结果

4 个答案: