Question

我必须在JSP中显示几个链接，HTML的结构对于每个链接都是相同的，所以我使用struts2 taglib迭代器来构建它。问题是我不知道如何构建链接本身：

我的JSP

<%@ taglib prefix="s" uri="/struts-tags"%>
<head></head>
<div class="menuBotoes">
    <s:iterator value="links" var="link">
        <s:a namespace="link.nameSpace" action="link.action">
            <table cellpadding="0" cellspacing="0" class="tableBotaoMenu">
                <tr class="trCimaBotaoMenuSelect">
                    <td align="center" class="imagemBotaoMenuSelect"><img src="<s:url value="/includes/imagens/global/botoes/grafico.png" />" /></td>
                    <td align="left" class="descricaoBotaoMenuSelect"><s:property value="textoLink" /></td>
                </tr>
                <tr class="trBaixoBotaoMenuSelect">
                    <td align="center" class="imagemBotaoMenuSelect" colspan="2"><s:property value="projeto" /></td>
                </tr>
            </table>
        </s:a>
    </s:iterator>
</div>

在JSP中迭代的对象是：

public enum LinksRelatorios {

    1("Caixa Visita", "/relatorios/", "iniciarRelatorioCaixaVisita", "TISS"),
    2("Caixa Visita Empresa", "/relatorios/", "iniciarRelatorioCaixaVisitaEmpresa", "TISS"),
    3("Produtividade Internação Domiciliar", "/relatorios/", "iniciarRelatorioInternacaoDomiciliar", "TISS"),
    4("Pendências", "/relatorios/", "iniciarRelatorioPendencias", "TISS"),
    5("Solicitação Inicial", "/relatorios/", "iniciarRelatorioSolicitacaoInicial", "TISS"),
    6("Solicitação Prorrogação", "/relatorios/", "iniciarRelatorioSolicitacaoProrrogacao", "TISS"),
    7("Tempo Resposta", "/relatorios/", "iniciarRelatorioTempoResposta", "TISS");

    private String textoLink;
    private String nameSpace;
    private String action;
    private String projeto;

    private LinksRelatorios(final String textoLinkParam, final String nameSpaceParam, final String actionParam,
            final String projetoParam) {
        this.textoLink = textoLinkParam;
        this.nameSpace = nameSpaceParam;
        this.action = actionParam;
        this.projeto = projetoParam;
    }

    public String getTextoLink() {
        return this.textoLink;
    }

    public String getNameSpace() {
        return this.nameSpace;
    }

    public String getAction() {
        return this.action;
    }

    public String getProjeto() {
        return this.projeto;
    }
}

我的行动

@Controller
@Scope("request")
public class InicioAction extends BaseAction {

    private static final long serialVersionUID = -1161409943678292285L;

    private static final LinksRelatorios[] links = LinksRelatorios.values();

    public String inicio() {
        this.addActionMessage(this.getText("msg.sucesso.saudacao.mensagem", new String[] { (String) BaseAction
                .getSession().getAttribute(Constantes.PERFIL) }));
        return Action.SUCCESS;
    }

    public String iniciarRelatoriosPorProjeto() {
        return Action.SUCCESS;
    }

    public String iniciarRelatoriosFiltro() {
        return Action.SUCCESS;
    }

    public static LinksRelatorios[] getLinks() {
        return InicioAction.links;
    }
}

我试过用过 <s:a namespace="link.nameSpace" action="link.action">，< s:a namespace="%{link.nameSpace}" action="%{link.action}">，<s:a namespace="#link.nameSpace" action="#link.action">，但似乎无效。

在有人要求之前，枚举工作正常，在我的JSP中我有<s:property value="projeto" />和<s:property value="textoLink" />，这些是来自枚举的属性。

我已经阅读了http://struts.apache.org/release/2.3.x/docs/using-struts-2-tags.html，http://struts.apache.org/release/2.3.x/docs/a.html和http://struts.apache.org/release/2.3.x/docs/url.html中的在线官方文档，但是与PrimeFaces或RichFaces等框架相比，示例部分实际上相当差。展示。

Answer 1

使用以下代码

<s:a namespace="%{#link.nameSpace}" action="%{#link.action}">

使用％{}使struts2评估{}内表达式的内容，然后将结果赋值给属性。

有关详细信息，请参阅http://struts.apache.org/release/2.0.x/docs/tag-syntax.html。

Struts2 - 如何在不事先知道我将使用的操作的情况下使用<s：a>？</s：a>

1 个答案: