我为登录编写了以下代码,但是当我在email-id之后输入“\”时,它接受并成功登录(它不接受任何其他符号或字符只接受“\”)。
我不希望它以“\”登录。“
@Override
public void onCreate(Bundle savedInstanceState) {
try {
super.onCreate(savedInstanceState);
requestWindowFeature(Window.FEATURE_NO_TITLE);
getWindow().setSoftInputMode(
WindowManager.LayoutParams.SOFT_INPUT_STATE_ALWAYS_HIDDEN);
setContentView(R.layout.main);
WiztangoBaseApplication.InitDialogBox(WiztangoActivity.this);
this.pref = PreferenceManager.getDefaultSharedPreferences(this);
loginStatus = (TextView)findViewById(R.id.login_status);
register = (Button) findViewById(R.id.btnregister);
register.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
RegisterIntent();
}
});
login = (Button) findViewById(R.id.btlogin);
password = (EditText) findViewById(R.id.txtPwd);
username = (EditText) findViewById(R.id.txtemail);
saveLoginCheckBox = (CheckBox)findViewById(R.id.saveLoginCheckBox);
pref = getSharedPreferences(Constants.PREFS_NAME,
MODE_PRIVATE);
String usernamestr = pref.getString(Constants.PREF_USERNAME, "");
String passwordsharestr = pref.getString(Constants.PREF_PASSWORD,
"");
username.setText(usernamestr);
password.setText(passwordsharestr);
saveLogin = pref.getBoolean("saveLogin", false);
if (saveLogin == true) {
username.setText(usernamestr);
password.setText(passwordsharestr);
saveLoginCheckBox.setChecked(true);
}
login.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
try {
//Constants.clearInfo();
getSharedPreferences(Constants.PREFS_NAME, MODE_PRIVATE)
.edit()
.putString(Constants.PREF_USERNAME,
username.getText().toString())
.putString(Constants.PREF_PASSWORD,
password.getText().toString())
.putString(Constants.PREF_CHECKED, "TRUE")
.commit();
if (username.getText().toString().trim().equals("")) {
username.setError(Html
.fromHtml("Please Enter Username"));
username.requestFocus();
} else if (password.getText().toString().trim()
.equals("")) {
password.setError(Html
.fromHtml("Please Enter Password"));
password.requestFocus();
} else {
if (Constants
.checkInternetConnection(WiztangoActivity.this)) {
Constants.userpass = password.getText()
.toString();
new AuthenticData().execute();
} else {
WiztangoBaseApplication.ShowThisDialog("Error",
"Please check internet connection.");
}
if (saveLoginCheckBox.isChecked()) {
prefEditor.putBoolean("saveLogin", true);
prefEditor.putString(Constants.PREF_USERNAME,
username.getText().toString());
prefEditor.putString(Constants.PREF_PASSWORD,
password.getText().toString());
saveLoginCheckBox.setChecked(true);
prefEditor.commit();
} else {
SharedPreferences mPreferences = getSharedPreferences(Constants.PREFS_NAME, MODE_PRIVATE);
SharedPreferences.Editor editor=mPreferences.edit();
editor.remove(Constants.PREF_USERNAME);
editor.remove(Constants.PREF_PASSWORD);
editor.commit();
}
}
} catch (Exception e) {
Log.e("Exception In Wiztango/", e.toString());
e.printStackTrace();
}
}
});
} catch (Exception e) {
Log.e("Exception In Wiztango/", e.toString());
e.printStackTrace();
}
}
答案 0 :(得分:3)
内置模式提供电子邮件验证,如:
if (!android.util.Patterns.EMAIL_ADDRESS.matcher(emailStr).matches() && !TextUtils.isEmpty(emailStr)) {
emailEditText.setError("Invalid Email");
emailEditText.requestFocus();
}
答案 1 :(得分:1)
Heyy,请在此处查看此答案:https://stackoverflow.com/a/7882950/1739882
它说:
public final static boolean isValidEmail(CharSequence target) {
if (target == null) {
return false;
} else {
return android.util.Patterns.EMAIL_ADDRESS.matcher(target).matches();
}
}
答案 2 :(得分:0)
您可以使用此代码进行检查是否为有效电子邮件:
public final static boolean isValidEmail(CharSequence target) {
if (target == null) {
return false;
} else {
return android.util.Patterns.EMAIL_ADDRESS.matcher(target).matches();
}
}
答案 3 :(得分:0)
最佳方法
在一种方法中验证电子邮件和isEmpty。
public final static boolean isValidEmail(CharSequence target)
{
return !TextUtils.isEmpty(target) && android.util.Patterns.EMAIL_ADDRESS.matcher(target).matches();
}
答案 4 :(得分:-1)
public static boolean isEmailValid(String email) {
boolean isValid = false;
String expression = "^[\\w\\.-]+@([\\w\\-]+\\.)+[A-Z]{2,4}$";
CharSequence inputStr = email;
Pattern pattern = Pattern.compile(expression, Pattern.CASE_INSENSITIVE);
Matcher matcher = pattern.matcher(inputStr);
if (matcher.matches()) {
isValid = true;
}
return isValid;
}
答案 5 :(得分:-1)
试试这段代码: -
public final static boolean isValidEmail(CharSequence target) {
if (target == null) {
return false;
} else {
return android.util.Patterns.EMAIL_ADDRESS.matcher(target).matches();
}
}
答案 6 :(得分:-1)
尝试使用以下方法验证电子邮件地址。
private boolean validateEmail(EditText editText, String p_nullMsg, String p_invalidMsg)
{
boolean m_isValid = false;
try
{
if (p_editText != null)
{
if(validateForNull(editText,p_nullMsg))
{
Pattern m_pattern = Pattern.compile("([\\w\\-]([\\.\\w])+[\\w]+@([\\w\\-]+\\.)+[A-Za-z]{2,4})");
Matcher m_matcher = m_pattern.matcher(editText.getText().toString().trim());
if (!m_matcher.matches() && editText.getText().toString().trim().length() > 0)
{
m_isValid = false;
editText.setError(p_invalidMsg);
}
else
{
m_isValid = true;
}
}
else
{
m_isValid = false;
}
}
else
{
m_isValid = false;
}
}
catch(Throwable p_e)
{
p_e.printStackTrace(); // Error handling if application crashes
}
return m_isValid;
}