Question

使用codeigniter从mysql中检索值时遇到一个问题。

我有一个表名任务，其中有一个assigneduserid字段。

表格 - 任务：

id  | title         | Title     | assigneduserid
--------------------------------------------------------
1   | Workspace     |PMS        | 23,21

表格 - 用户

id  | title 
-----------------
23  | Ashish
21  | Ritesh

在assigneduserid字段中，该字段中有两个值为23,21。

我想在用户登录中显示任务标题。但它只显示给Ashish登录。我怎么解决呢？

以下是我的模特： -

function getTask($id, $is_master_admin) {
        $this->db->select('task.*, workspace.title as workspacetitle, user.title as usertitle');
        $this->db->join(WORKSPACE, WORKSPACE . '.id = ' . TASK . '.workspaceid', 'inner');
        $this->db->join(USER, USER . '.id = ' . TASK . '.userid', 'inner');
        $this->db->from(TASK);
        $this->db->group_by('task.id');
        if (!$is_master_admin) {
            $this->db->where(USER . '.id', $id);
        }
        $this->db->where(TASK . '.tasktypeid', '1');
        $query = $this->db->get();
        if ($query->num_rows() > 0) {
            return $query->result();
        } else {
            return false;
        }
    }

任何人都可以帮忙吗？

Answer 1

function getTask($id, $is_master_admin) {
 $data= $this->db->group_by('task.id')->get('task')->result();//check what value your getting in data and then use foreach and select the user from the user table 
  foreach($data as $value):
   $array= $this->db->where('id',$value->id)->get('user')->result();      
  endforeach;   
}

Answer 2

尝试，尚未检查，

$tsql =  " SELECT task.*, workspace.title AS workspacetitle, GROUP_CONCAT(user.title ORDER BY id) AS usertitle ".
         " INNER JOIN ". WORKSPACE ." ON ". WORKSPACE .".id = " . TASK . ".workspaceid ".
         " INNER JOIN USER ON FIND_IN_SET(".USER . ".id, ". TASK .".assigneduserid ) > 0  ".
         " FROM ". TASK ;


        if (!$is_master_admin) {
           $tsql .= " WHERE ". USER . ".id =". $id;
        }


   $tsql .= " WHERE ". TASK . ".tasktypeid =1 ";        
   $tsql .= " GROUP BY ". TASK .".id ";
$query = $this->db->query($tsql);

从mysql的单个字段（Codeigniter）访问逗号分隔符后的值

2 个答案: