使用数字键将JavaScript对象转换为数组

Question

我有一个这样的对象作为来自服务器的JSON响应返回：

{"0":"1","1":"2","2":"3","3":"4"}

我想将它转换为像这样的JavaScript数组：

["1","2","3","4"]

有最佳方法吗？无论我在哪里阅读，人们都在使用循环来使用复杂的逻辑。那么有没有其他方法可以做到这一点？

Answer 1

jQuery＆＃39; s $.map

实际上非常直接

var arr = $.map(obj, function(el) { return el });

FIDDLE

并且在没有jQuery的情况下也很容易，将键转换为数组，然后使用Array.map

映射值

var arr = Object.keys(obj).map(function(k) { return obj[k] });

FIDDLE

假设它已经被解析为javascript对象，并且实际上并不是JSON，这是一种字符串格式，在这种情况下，需要运行JSON.parse同样。

在ES2015中有Object.values来救援，这让这变得轻而易举

var arr = Object.values(obj);

Answer 2

var json = '{"0":"1","1":"2","2":"3","3":"4"}';

var parsed = JSON.parse(json);

var arr = [];

for(var x in parsed){
  arr.push(parsed[x]);
}

希望这就是你所追求的！

Answer 3

你只需要像

一样

var data = {
    "0": "1",
    "1": "2",
    "2": "3",
    "3": "4"
};
var arr = [];
for (var prop in data) {
    arr.push(data[prop]);
}
console.log(arr);

DEMO

Answer 4

没有什么比“JSON对象” - JSON是序列化表示法。

如果你想将 javascript对象转换为 javascript数组，你要么编写自己的循环[这不会那么复杂！]，或者你依赖于underscore.js _.toArray()方法：

var obj = {"0":"1","1":"2","2":"3","3":"4"};
var yourArray = _(obj).toArray();

Answer 5

这里没什么难的。循环遍历对象元素并将它们分配给数组

var obj = {"0":"1","1":"2","2":"3","3":"4"};
var arr = [];
for (elem in obj) {
   arr.push(obj[elem]);
}

http://jsfiddle.net/Qq2aM/

Answer 6

var JsonObj= {"0":"1","1":"2","2":"3","3":"4"};
var array = [];
for(var i in JsonObj) {
    if(JsonObj.hasOwnProperty(i) && !isNaN(+i)) {
        array[+i] = JsonObj[i];
    }
}

DEMO

Answer 7

试试这个：

var newArr = [];
$.each(JSONObject.results.bindings, function(i, obj) {
    newArr.push([obj.value]);
});

Answer 8

使用原始javascript，假设你有：

var j = {0: "1", 1: "2", 2: "3", 3: "4"};

您可以使用以下内容获取值：

Object.keys(j).map(function(_) { return j[_]; })

输出：

["1", "2", "3", "4"]

Answer 9

不确定我在这里缺少什么，但只是尝试下面的代码就可以了。我在这里错过了什么吗？

https://jsfiddle.net/vatsalpande/w3ew5bhq/

$(document).ready(function(){

var json = {
   "code" :"1", 
   "data" : { 
    "0" : {"id":"1","score":"44"},
    "1" : {"id":"1","score":"44"}
    }
  };

  createUpdatedJson();

  function createUpdatedJson(){

    var updatedJson = json;

    updatedJson.data = [updatedJson.data];

    $('#jsondata').html(JSON.stringify(updatedJson));


    console.log(JSON.stringify(updatedJson));
  }
 })

Answer 10

var obj = {"0":"1","1":"2","2":"3","3":"4"};

var vals = Object.values(obj);

console.log(vals); //["1", "2", "3", "4"]

问题的另一种选择

var vals = Object.values(JSON.parse(obj)); //where json needs to be parsed

Answer 11

假设您有类似以下的值

var obj = {"0":"1","1":"2","2":"3","3":"4"};

然后您可以使用以下

将其转换为javascript数组

var arr = [];
json = JSON.stringify(eval('(' + obj + ')')); //convert to json string
arr = $.parseJSON(json); //convert to javascript array

这适用于将json转换为多diminsional javascript数组。

除了我在这里提到的方法之外，使用php json编码的字符串时，此页面上的其他任何方法似乎都不适合我。

Answer 12

以下是如何获取对象数组 和 然后对数组进行排序的示例。

  function osort(obj)
  {  // map the object to an array [key, obj[key]]
    return Object.keys(obj).map(function(key) { return [key, obj[key]] }).sort(
      function (keya, keyb)
      { // sort(from largest to smallest)
          return keyb[1] - keya[1];
      }
    );
  }

Answer 13

这是最好的解决方案。我想是的。

Object.keys(obj).map(function(k){return {key: k, value: obj[k]}})

Answer 14

您可以使用PHP将json对象转换为Array和String。

$data='{"resultList":[{"id":"1839","displayName":"Analytics","subLine":""},{"id":"1015","displayName":"Automation","subLine":""},{"id":"1084","displayName":"Aviation","subLine":""},{"id":"554","displayName":"Apparel","subLine":""},{"id":"875","displayName":"Aerospace","subLine":""},{"id":"1990","displayName":"Account Reconciliation","subLine":""},{"id":"3657","displayName":"Android","subLine":""},{"id":"1262","displayName":"Apache","subLine":""},{"id":"1440","displayName":"Acting","subLine":""},{"id":"710","displayName":"Aircraft","subLine":""},{"id":"12187","displayName":"AAC","subLine":""}, {"id":"20365","displayName":"AAT","subLine":""}, {"id":"7849","displayName":"AAP","subLine":""}, {"id":"20511","displayName":"AACR2","subLine":""}, {"id":"28585","displayName":"AASHTO","subLine":""}, {"id":"45191","displayName":"AAMS","subLine":""}]}';

$b=json_decode($data);

$i=0;
while($b->{'resultList'}[$i])
{
    print_r($b->{'resultList'}[$i]->{'displayName'});
    echo "<br />";
    $i++;
}

Answer 15

      var data = [];

      data  = {{ jdata|safe }}; //parse through js
      var i = 0 ;
      for (i=0;i<data.length;i++){
         data[i] = data[i].value;
      }

Answer 16

您可以将Object.assign()与空数组文字[]用作target：

const input = {
  "0": "1",
  "1": "2",
  "2": "3",
  "3": "4"
}

const output = Object.assign([], input)

console.log(output)

如果您选中polyfill，Object.assign(target, ...sources)只是将所有可枚举的属性从source对象复制到目标对象。如果target是一个数组，它将数字键添加到数组文字中并返回该target数组对象。